Question

Solve the equation.9x^2 + 16 = 0

Answer 1

Step 1

Given;

$9x^2+16=0$

Required: To solve the equation.

Step 2

Solve the equation

$\begin{gathered} 9x^2+16-16=0-16 \\ 9x^2=-16 \\ \frac{9x^2}{9}=\frac{-16}{9} \\ x^2=-\frac{16}{9} \\ \sqrt{x^2}=\pm\sqrt{\frac{-16}{9}} \\ x=\sqrt{-\frac{16}{9}},\:x=-\sqrt{-\frac{16}{9}} \\ x=i\frac{4}{3},\:x=-i\frac{4}{3} \end{gathered}$

Answer;

$x=\frac{4}{3}i,\text{ -}\frac{4}{3}i$