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xenn [34]
2 years ago
6

For installation with a 300-kVA, 3-phase transformer, a 480-volt primary, and a 240-volt secondary. Calculate the maximum overcu

rrent protection value (not the fuse or circuit breaker rating) using the protection method for primary-only protection. (Round the FINAL answer to two decimal places.)
Mathematics
1 answer:
Novay_Z [31]2 years ago
6 0

By using the protection method for primary-only protection, the maximum overcurrent protection (MOCP) is equal to 451.59 Amperes.

<h3>What is MOCP?</h3>

In Electrical engineering, MOCP is an abbreviation for maximum overcurrent protection and it can be defined as the maximum allowable current rating that is required for any circuit breaker or fuse, in order to properly protect an electrical equipment, especially under uncertain or anticipated fault conditions.

Mathematically, the amount of current flowing through the primary winding of a three-phase transformer can be calculated by using this mathematical expression:

Current, I = 3-phase KVA/(1.73 × Voltage)

Substituting the given parameters into the formula, we have;

Current, I = 300,000/(1.73 × 480)

Current, I = 300,000/830.4

Current, I = 361.27 Amperes.

By using the protection method for primary-only protection, the maximum overcurrent with 25% above the current is given by:

Maximum overcurrent = 125% × Current

Maximum overcurrent = 125/100 × 361.27

Maximum overcurrent = 45,158.75/100

Maximum overcurrent = 451.5875 ≈ 451.59 Amperes.

Learn more about maximum overcurrent protection here: brainly.com/question/14284905

#SPJ1

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