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zepelin [54]
3 years ago
14

Help please answer this .... is this bettter?

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

x = 53 degrees

Step-by-step explanation:

Alternate exterior angles are equal if  two parallel lines are cut by a transversal.

 If  m and n are parallel, then

3x-28 = 2x+25

Subtract 2x from each side.

3x-28-2x = 2x+25-2x

x-28 =25

Add 28 to each side.

x-28+28 = 25+28

x = 53

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What is the domain function on the graph
sattari [20]
ANSWER

All real numbers greater or equal to -3.


EXPLANATION

The domain of the given function are values of x that make the function defined.


We can see from the graph that, the domain are x-values greater than or equal to -3.



In other words, we can find a corresponding y-value for all x-values greater than or equal to -3.

The correct answer is option D.
4 0
3 years ago
Read 2 more answers
What is the derivative of y=ln(ln(x))?
Marysya12 [62]
Y=ln(ln(x)) y'=(1/x)/Ln(x)=1/xln(x)
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3 years ago
Tom has 7/8 gallons of paint. He used 1/2 gallon of paint on a project. He uses the steps to show how much paint he had when he
WINSTONCH [101]

He made his mistake in Step 2. Tom should have subtracted 4/8 instead of 1/8. The mistake is that he was not consistent when he multiplied Denominators (bottom number) must be the same when handling fractions so Tom must multiply both the numerator and denominator by the SAME number to balance it out. 1/2 x 4/4= 4/8. Subtract. 7/8 - 4/8= 3/8. Tom has 3/8 of a gallon of paint leftover.

4 0
3 years ago
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Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

7 0
3 years ago
If someone could help! ​
ad-work [718]

Step-by-step explanation:

This time round, use SOH method (Sin angle = Opposite/Hypotenuse)

given Opposite = 7

Hypotenuse = 10

\sin(x)  =  \frac{opposite}{hypotenuse}  \\  \sin(x)  =  \frac{7}{10}  \\ x =  {sin}^{ - 1} ( \frac{7}{10} ) \\  = 44.4deg(nearest \: tenth)

4 0
3 years ago
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