Scott is playing a game in which he rolls a number cube with faces numbered 1through 6 and spins the spinner shown below one tim
e each.How many unique combinations where the number on the cube is greater than 2 andthe number on the spinner is less than 9 are possible?A. 8 B. 15C. 24D. 60
1 answer:
Solution:
The total number of possiblities rolling a number cube with faces numbered 1 to 6 is;
And the total number of possibilities spining the spinner is;
The number of possibility where outcome on the cube is greater than 2 is;
And the number on the spinner less than 9 is;
Hence, the unique combination is;
CORRECT OPTION: A
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The final result is: 20x^3 + 62x^2 + 8x - 64.
Answer:
0.999987
Step-by-step explanation:
Given that
The user is a legitimate one = E₁
The user is a fraudulent one = E₂
The same user originates calls from two metropolitan areas = A
Use Bay's Theorem to solve the problem
P(E₁) = 0.0131% = 0.000131
P(E₂) = 1 - P(E₁) = 0.999869
P(A/E₁) = 3% = 0.03
P(A/E₂) = 30% = 0.3
Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :
= 0.999986898 ≈ 0.999987
Answer:
6r+7=13+7r
6r+7=7r+13
6r+7−7r=7r+13−7r
−r+7=13
−r+7−7=13−7
−r=6
=
r=−6
Step-by-step explanation:
:) This is the answer