<u>General method</u><u>:</u>
Given numbers are 1.3 bar and 1.4 bar
- 1.3 bar = 1.333...
- 1.4 bar = 1.444...
Two rational numbers between them
= 1.3222... and 1.43333...
<u>Mean Method</u><u>:</u>
Let X = 1.333... → → →eqn(i)
since the periodicity is 1 then multiply eqn(i) with 10
⇛10×X = 1.333...×10
⇛10X = 13.333... → → →eqn(ii)
Subtract eqn(ii)-eqn(i)
10X = 13.333...
X = 1.333...
(-)
____________
9X = 12.000...
____________
⇛9X = 12
⇛X = 12/9
⇛X = 4/3
and
Let X = 1.444... → → →eqn(i)
since the periodicity is 1 then multiply eqn(i) with 10
⇛10×X = 1.444...×10
⇛10X = 14.444...→ → →eqn(ii)
Subtract eqn(ii)-eqn(i)
10X = 14.444...
X = 1.444...
(-)
____________
9X = 13.000...
____________
⇛9X = 13
⇛X = 13/9
Now we have 12/9 and 13/9
The rational number between them by mean method (a+b)/2
⇛{(12/9)+(13/9)}/2
⇛(25/9)/2
⇛25/18
and Second rational number
⇛{(12/9)+(25/18)}/2
⇛{(24+25)/18}/2
⇛(49/18)/2
⇛49/36
<u>Answer</u><u>:</u> The two rational numbers between them are 25/18 and 49/36.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?
brainly.com/question/85169?referrer
Answer:
(x+a)(x+b)= x²+(a+b)x+ab
This is an identity of mathematics! not an equation.
The current area is 15 x 9 = 135 square feet.
He wants to increase both the length and width by X:
Set up an equation:
(15 +x) * (9 +x) = 135 * 2
Simplify :
x^2 + 24x + 135 = 270
Subtract 270 from both sides:
x^2 + 24x - 135 = 0
Use the quadratic formula to solve for x:
-24 +/- √(24^2 - 4(1*-135) / 2*1
x = 4.7 or -28.7
The answer has to be a positive value, so x = 4.7 feet.
Answer: 11
Step-by-step explanation:
48+4=52
5×11=55
She needs 11 boxes to cover all expenses.
Answer:
x>4
Step-by-step explanation:
Sorry if there is any mistakes
