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Wewaii [24]
2 years ago
5

How many times can 7 go into 1000

Mathematics
1 answer:
Mariana [72]2 years ago
5 0

Answer:

7 can go into 1000 142 6/7 times. This is a remainder equation, but that is how many times 7 can go into 1000.

Hope this helps!

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Solve each equation.<br> X – 10 = 4<br> Math
garik1379 [7]

Answer:

x=14

Step-by-step explanation:

7 0
3 years ago
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H=-16t^2+46t+6 after how many seconds will the ball hit the ground?
ANEK [815]
Ball hit the ground is when the function equals zero
0=-16t^2+46t+6
we can't factor so use quadraticformula

for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
x=\frac{-46+/- \sqrt{46^2-4(-16)(6)} }{2(-16)}
x=\frac{-46+/- \sqrt{2116+384} }{-32}
x=\frac{-46+/- \sqrt{2500} }{-32}
x=\frac{-46+/- 50 }{-32}
x=\frac{-46+ 50 }{-32} or \frac{-46- 50 }{-32}
x=\frac{4}{-32} or x=\frac{-96}{-32}
x=-1/6 or x=3

we cannot have negative time because time starts at 0
disregard -1/6 as a possible answer


answer is after 3 seconds

4 0
3 years ago
Math homeworkkkkkkkkkkkk
Blababa [14]
Hopefully these are correct lol, make sure to check it with a classmate. but i tried :)

6 0
4 years ago
Find the value of 7!?
Schach [20]
The question isn’t clear, post the question so I could help :) !
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3 years ago
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How do I set up the equation for this word problem? A takes 1/2 of the diamonds plus 1 from the table. B takes 2/3 of what remai
nalin [4]

The first thief takes (1/2 x + 1) .  What remains ?   x - (1/2x + 1)

So the 2nd thief takes  2/3 of  [  x - (1/2x + 1) ]

   What remains ?    x - 2/3 [ x - (1/2x + 1) ]

So the 3rd thief takes    2/3 of  { x - 2/3 [ x - (1/2x + 1) ] }  and he takes 1 more .

   What remains ?    x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )

And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..

The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.  
===============================================
This is a lot harder than just solving the problem with logic and
waving your hands in the air.  Here's how you would do that:

Start from the end and work backwards:

-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.

Thank you for your generous 5 points.


 
3 0
3 years ago
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