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3 years ago

A rectangle has an square meters. The width is 1\5 meter. What is the length of the rectangle?

Mathematics

1 answer:

Alecsey [184]3 years ago

6 0

Answer:

The length would be 5 meters

Step-by-step explanation:

To get this value, start with the area formula.

A = LW

Next input the known values for area and width

1 = L1/5

Now multiply each side by 5

5 = L

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Plz help I’ll mark brainliest

jeka94

Answer:

Step-by-step explanation:

To find the measure of angle x we use cosine

$\cos( \alpha ) = \frac{adjacent}{hypotenuse}$

From the question

PO is the hypotenuse = 13

The adjacent is 12

Substitute the values into the above formula

That's

$\cos(x) = \frac{12}{13}$

$x = \cos^{ - 1} ( \frac{12}{13} )$

x = 22.6198

We have the final answer as

<h3>x = 22.62° to the nearest hundredth</h3>

Hope this helps you

3 0

3 years ago

Read 2 more answers

Jamie has just finished writing a research paper. She has hires a typist who will type the paper on the computer for her. The ty

never [62]

<span>The maximum size is 40 pages at $3.50 and 16 pages at $8

c=40*3.50+16*8
c=140+128
c=$268</span>

3 0

3 years ago

What is the sum of the first 40 positive odd integers?

nika2105 [10]

Answer:

1600

Step-by-step explanation:

$\text{Number of terms}, ~n = 40\\\\\text{Sum of n odd integers} = n^2 = 40^2 = 1600$

6 0

2 years ago

1) What is the GCF for the polynomial 4x3 - 2x2y?

Dafna1 [17]

(1)the GCF for the polynomial $4x^3 - 2x^2y$

4x^3 = 2*2* x* x* x

2x^2y = 2*x*x*y

Greatest common factor is $2*x*x = 2x^2$

(2) the GCF for the polynomial $8x^4y + 6x^2y^2$

$8x^4y = 2*2*2*x*x*x*x*y$

$6x^2y^2 = 3*2*x*x*y*y$

GCF is $2*x*x*y=2x^2y$

(3) the GCF for the polynomial $12x^3y^2 - 20x^5y^3$

$12x^3y^2 = 2*2*3*x*x*x*y*y$

$20x^5y^3=5*2*2*x*x*x*x*x*y*y*y$

GCF is $2*2*x*x*x*y*y= 4x^3y^2$

(4) the GCF for the polynomial $-10x^3y^4 - 16x^5y^2$

$-10x^3y^4 =-2*5*x*x*x*y*y*y*y$

$-16x^5y^2=-2*2*2*2*x*x*x*x*x*y*y$

GCF is $-2*x*x*x*y*y= -2x^3y^2$

3 0

3 years ago

Read 2 more answers

Given n(A) = 1300, n(A U B) = 2290, and n(A n B) = 360, find n(B).

Stels [109]

Answer:

n(B) = 1350

Step-by-step explanation:

Using Venn sets, we have that:

$n(A \cup B) = n(A) + n(B) - n(A \cap B)$

Three values are given in the exercise.

The other is n(B), which we have to find. So

$n(A \cup B) = n(A) + n(B) - n(A \cap B)$

$2290 = 1300 + n(B) - 360$

$940 + n(B) = 2290$

$n(B) = 2290 - 940 = 1350$

n(B) = 1350

3 0

3 years ago