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neonofarm [45]
1 year ago
6

If you roll a standard six-sided die, what is the probability that you get a 1, 2, 3, 5, or 6? give your answer as a simplified

fraction.
Mathematics
1 answer:
Alexxandr [17]1 year ago
8 0

The probability of getting 1, 2, 3, 5, or 6 when you roll a standard six-sided die is 5/6

<h3>How to find the probability of getting a 1, 2, 3, 5, or 6 when you roll a standard six-sided?</h3>

The given parameters are:

Sample space = {1, 2, 3, 4, 5, 6}

So, we have

P(1)  1/6

P(2) = 1/6

P(3) = 1/6

P(5) = 1/6

P(6) = 1/6

The probability of getting 1, 2, 3, 5, or 6 when you roll a standard six-sided die is calculated as:

P = 1/6 + 1/6 + 1/6 + 1/6 + 1/6

So, we have

P =5/6

Hence, the probability of getting 1, 2, 3, 5, or 6 when you roll a standard six-sided die is 5/6

Read more about probability at

brainly.com/question/24756209

#SPJ4

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Step-by-step explanation:

Let M = Malachy's share

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We have three conditions:

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Substitute (2) into (3)             (4) M + 3B + B = 150

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Substitute (2) into (1)                                  M = 2(3B)

                                               (6)                M = 6B

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Substitute (7) into (2)                                  P = 3×15

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Solve for M:

Substitute (8) into (1)                                  M = 2×45

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Step-by-step explanation:

(i) x + 3 = 0

L.H.S. = x + 3

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(ii) x + 3 = 0

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By putting x = 0,

L.H.S. = 0 + 3 = 3 ≠ R.H.S.

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∴No, the equation is not satisfied.

(xi) = 2

L.H.S. =

By putting m = 6,

L.H.S. = = R.H.S.

∴ Yes, the equation is satisfied.

8 0
3 years ago
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