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1 year ago

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Which phrase best describes f(x), graphed on the coordinate plane below?64(0)2-х2-46Of(x) is an odd function.Of(x) is an even fu

nction.Of(x) is both odd and even.Of(x) is neither odd nor even.

1 answer:

Marianna [84]1 year ago

8 0

Functions which satisfy the following:

$f(-x)=-f(x)$

are odd functions

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Can someone solve for me it’s either 75 or 105.

Wittaler [7]

Answer:

75

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A greeting card cost four dollars before tax. A customer has a 15% discount. Then the 5% sales tax is added. How much will the c

ss7ja [257]

Given:

Greeting card cost before tax = $4

Discount = 15%

Sales tax = 5%

To find:

How much will the customer pay for the card?

Solution:

It is given that the cost of the greeting card before tax is $4.

After 15% discount, the cost of the greeting card is:

Cost of card after discount $=4-\dfrac{15}{100}\times {4}$

$=4-0.6$

$=3.4$

The cost of card after 5% sales tax is:

Cost of card after tax $=3.4+\dfrac{5}{100}\times 3.4$

$=3.4+0.17$

$=3.57$

Therefore, the customer will pay $3.57 for the greeting card.

7 0

3 years ago

The account balance on April 1st is $50.51. On April 15th, a payment of $15.00 is made. On April 25th, a purchase of $19.27 is m

matrenka [14]

Hi there!

The true answer is as follows:

Finance charge = $0.76
To get this you need to take the account balance on April 1st and multiply by the annual rate of 18%, which looks like this:

$50.51 × 0.18 = 9.0918
Then you divide your answer by 12 for the months of the year to get:

9.0918 ÷ 12 = 0.75765
Which rounds to $0.76 for you finance charge

New balance = $55.54
To get this you take the account balance on April 1st and subtract the payment of $15.00 and then add the purchase of $19.27 and the finance charge of $0.76, like so:

$50.51 - $15.00 = $35.51 + $19.27 + $0.76 = $55.54

Your friend, ASIAX

3 0

3 years ago

Read 2 more answers

Ln(x+5) + lnx=5 answer me fast

pashok25 [27]

Answer:

9.936

Step-by-step explanation:

In(x+5)*x=5

ln(x^2+5x)=5

e^5=x^2+5x

148.4131=x^2+5x

x^2+5x-148.4131=0

x is 9.936 because logs can't be negative

7 0

3 years ago

Root 3 cosec140° - sec140°=4<br>prove that<br><br>

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

<u>Proof:</u>

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

$\frac{4(sin(420-140)) }{sin280}$

= $\frac{4sin280}{sin280}\\ = 4 \ Proved!$

3 0

3 years ago