The output is 21 because c is incremented by 3 until it surpasses 10 and the value of c is added to sum each time the loop runs.
I hope this helps!
Answer:
int counter = 0;
String userInput = "";
while (userInput != "stop") {
print "What pet do you have? ";
userInput = readInputLine();
if (userInput != "stop" ){
counter = counter + 1;
print "\nYou have one ";
print userInput;
print ". Total # of Pets: ";
print counter;
}
}
Explanation:
not sure what programming language you use, therefore the answer is pseudocode but it should give you an idea how to implement a piece of code for this problem.
Also, from the way you described the exercise I'm not sure if you always are supposed to reply with "you have one" + the pet or if you should count how often the same pet was entered.
You can probably refresh or log out or something.
Answer:
Option B (Static NAT) would be the correct choice.
Explanation:
- Static NAT seems to be a method of NAT methodology used to navigate as well as monitor internet usage from some kind of specific public IP address to something like a private IP address.
- Everything always allows the provision of web access to technology, repositories including network equipment inside a protected LAN with an unauthorized IP address.
Some other decisions made aren't relevant to the situation in question. So the above alternative is indeed the right one.
Answer:
The answer is "Connectors".
Explanation:
Please find the Connectors image in the attached file.
In this question, the connectors symbol is usually small throughout the flowcharts. It is used as a connection to display and changes throughout the flux. It was usually marked by major letters that indicate jump points. This diagram visually shows the sequence of events in a system and who is accountable.
