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Answer:
a) Therefore, the minimum number of bits required is 6.
b) Therefore, we can admit 4 more students to the class without requiring additional bit for each student's unique bit pattern
Explanation:
a) The number of unique bit patterns using <em>n</em> bits is calculated using .
In this case, there are 60 students, so, we need at least 60 unique bit pattern.
Where <em>n</em> is the number of bit required; we are to find <em>n</em>
We take the logarithm of both side:
Therefore, the minimum number of bits required is 6
b) How many more students can be admitted to the class without requiring additional bits for each student's unique bit pattern?
With 6 bits, we can represent up to unique bit pattern which is 64 unique bit patterns.
To get the number of additional bit:
64 - 60 = 4
Therefore, we can admit 4 more students to the class without requiring additional bit for each student's unique bit pattern