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ioda
3 years ago
6

I NEED HELP ASAP! : An initial population of 175 quail increases at an annual rate of 22%. Write an exponential function to mode

l the quail population. What will the approximate population be after 5 years?
Mathematics
1 answer:
goblinko [34]3 years ago
7 0

Answer:

About 473 quails.

P=175(1.22)^t

Step-by-step explanation:

Exponential equation with P_0 as the initial amount and rate of r is:

P=P_0(1+r)^t

P=175(1+.22)^t

P=175(1.22)^t

After 5 years the population will be:

P=175(1.22)^5

P \approx 472.9739

So the population will be about 473 quails.

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Answer:

Step-by-step explanation:

you will need to do:

j/9*2=2j/9

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3 years ago
T: 3(t + 3) + 5(3 + 2t) – 76 = 0
Setler [38]

Answer:

\huge\boxed{\sf t = 4}

Step-by-step explanation:

\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
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Find the volume of a cylinder with a radius of 3 meters and a height of 13 meters. Use 3.14 The volume of the cylinder is Type a
zvonat [6]
<h2><u>Question</u>:-</h2>

Find the volume of a cylinder with a radius of 3 meters and a height of 13 meters.

<h2><u>Answer</u>:-</h2>

<h3>Given:-</h3>

\bullet Radius (r) of a cylinder = 3 meters.

\bullet Height (h) of a cylinder = 13 meters.

<h3>To Find:-</h3>

The volume of a cylinder.

<h2>Solution:-</h2>

We know,

Formula of Volume of a cylinder is πr²h.

So, Volume of a cylinder = 3.14 × (3)² × 13

Volume of a cylinder = 3.14 × 3 × 3 × 13

Volume of a cylinder = 367.38 cubic meters.

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3 years ago
Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

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however, the last derivative must be equal to M. From there you can calculate g(t):

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Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

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