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EleoNora [17]
3 years ago
14

Patel bought a 2 lb bag of Trail Mix he poured 1/2 pound of trail mix into a bowl and divided the remaining amount into bags eac

h bag had 2 oz of Trail Mix how many bags did paddle use
Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

Patel used 0.125 lb bags

Step-by-step explanation:

Given that:

Patel bought 2 lb bag of Trail Mix

He then poured 1/2 pound of trail mix into a bowl

1/2 × 2= 1

i.e he poured 1 lb bag of the trail mix into a bowl

Then he divide the remaining amount into  bags in which each bag had 2 oz of trial mix.

Now; we knew that after he poured 1 lb bag of the trail mix into a bowl; there will be 1 lb bag remaining

So, he divide this remaining 1 lb bags into bags in which each bags contains 2 oz of the trail mix

So; what we need to find out is that , how many oz makes one lb

from the the conversion tables

16 oz = 1 lb

and it was said that each bag contain 2 oz

that implies that :

if;        16 oz = 1 lb

Then:   2 oz = x lb

16 oz * x lb = 2 oz * 1 lb

x lb = (2 oz * 1 lb )/16 oz

x lb = 0.125 lb

Thus; Patel used 0.125 lb bags

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ANTONII [103]

Answer:

42.2 cubic inch

Step-by-step explanation:

Applying,

V = πr²h/3.................... Equation 1

Where, r = radius of the circular base, h = height of the cone, π = pie.

But,

r = P/2π..................... Equation 2

Where P = circumference of the circular base.

Substitute equation 2 into equation 1

V = π(P/2π)²(h)/3

V = P²h/12π.................. Equation 3

From the question,

Given: h = 18.4 in, P = 9.3 in

Constant: π = 3.14

Substitute these values into equation 3

V = (9.3²)(18.4)/(12×3.14)

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4 0
3 years ago
A motorboat travels 168 kilometers in 4 hours going upstream. It travels 280 kilometers going downstream in the same amount of t
Grace [21]

Answer:

The speed of the boat is 56 km/hr

The rate of the current is 14 km/hr

Step-by-step explanation:

We are given the following;

  • Distance traveled upstream = 168 km
  • Time taken to travel upstream = 4 hours
  • Distance traveled down stream = 280 km
  • Time taken down stream = 4 hours

We are required to determine the speed of the boat in still water and the speed of the current.

We are going to take;

Speed of the boat as = x km/hr

Rate of flow of current = y km/hr

We can determine the speed of the boat upstream;

Speed = Distance ÷ time

               = 168 km ÷ 4 hours

               = 42 km/hr

But, the speed upstream is given by (x - y) km/hr

Therefore; ( x-y) km/hr = 42 km/hr ......................... Eqn 1

Speed of the boat down stream

    speed = 280 km ÷ 4 hours

                = 70 km/hr

But, the speed downstream is given by (x+y) km/hr

Therefore, x+y km/hr = 70 km/hr ........................... Eqn 2

Solving Eqn 1 and Eqn 2 simultaneously;

x - y = 42

x + y = 70

Eliminating x

-2y = - 28

    y = 14 km/hr

Solving for x,

x = 42 + y

   = 42 + 14

   = 56 km/hr

Therefore, the speed of the boat is 56 km/hr while the rate of the current is 14 km/hr

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4 years ago
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