This is what I get not sure if the problem on numerator is together if it is then . X^2+(a^2+1) x^2+a^2+1.
-----------------= ----------------- AX+1. Ax+1 Answer: a^2+x^2+1 ---------------- AX+1
If I wrote the actual problem wrong let me know. This is what I understood.
Answer:
Step-by-step explanation:
L=3(5280)/(2(380+250))
L=15840/1260
L=12.57
So to walk three miles one must walk around the garden 12.57 times.
Parallel have same slope
Perpendicular have opposite reciprocal slopes. Ex. 2/3 is slope of one line so the perpendicular line would have slope of -3/2.
Find slopes of these lines.
-4x-5y=-4
-4x+4 =5y
Divide by 5
Y= -4x/5 +4/5
Second line: 10x-8y=-1
10x+1=8y
Divide by 8
10x/8 +1/8 =y
Y= 5x/4 +1/8
So if you look at slope of line 1= -4/5 and line 2 it’s 5/4 so these both are perpendicular.
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5
Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students
Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students
Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68
Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
Answer: D
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