How many moles of CaCl2 are required to prepare 2.00 liters of 0.700 M CaCl2
1 answer:
As we know,
Molarity = Moles / Vol. of Solution ------- (1)
Data Given:
Molarity = 0.70 mol.L⁻¹
Volume = 2.00 L
To Find:
Moles = ?
Solution:
Solve eq. 1 for Moles,
Moles = Molarity × Volume
Putting Values,
Moles = 0.70 mol.L⁻¹ × 2.00 L
Moles = 1.4 mol
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