Which of the following is an empirical formula? a) H2O2 b) H2O c) C2H2 d) C4H8

Which of the following is a liquid someone help!!!!!

Leya [2.2K]

Answer:

juice, C

Explanation:

4 0

3 years ago

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a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what

jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

$P\cdot V = n\cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure, measured in kilopascals.

$V$ - Volume, measured in liters.

$n$ - Molar quantity, measured in moles.

$T$ - Temperature, measured in Kelvin.

$R_{u}$ - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

$\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}}$ (2)

Where:

$P_{1}$ , $P_{2}$ - Initial and final pressure, measured in kilopascals.

$V_{1}$ , $V_{2}$ - Initial and final volume, measured in liters.

$T_{1}$ , $T_{2}$ - Initial and final temperature, measured in Kelvin.

If we know that $P_{1} = 121\,kPa$ , $P_{2} = 202\,kPa$ , $V_{1} = 2.7\,L$ , $T_{1} = 288\,K$ and $T_{2} = 303\,K$ , the final volume of the gas is:

$V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}$

$V_{2} = 1.702\,L$

The gas will occupy a volume of 1.702 liters.

6 0

3 years ago

A solution of ammonium carbonate is mixed with a solution of magnesium nitrate. If magnesium carbonate is insoluble in water, wh

Dahasolnce [82]

Tbh I don’t know I tried to answer it

3 0

3 years ago

The idea that light can act like packets led to what new field on science?

Elenna [48]

Light acting as 'packets' of exact amounts of energy (a particle-like quality) called quanta led to the development of quantum mechanics. Light also has wave qualities (wavelength, frequency, amplitude) which is referred to as particle-wave duality.

5 0

2 years ago

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How much heat is absorbed by 15.5g of water when it's temperature is increased from 20.0C the specific heat of the water is 4.18

Anuta_ua [19.1K]

Hello!

The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):

$Q=m*C* \Delta T=15,5 g * 4,184 (J/g^\circ C) * 20 ^\circ C=1297,04 J$

So, the Heat absorbed by water is 1297,04 J

Have a nice day!

7 0

3 years ago