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ikadub [295]
2 years ago
11

Which of the following is an empirical formula? a) H2O2 b) H2O c) C2H2 d) C4H8

Chemistry
1 answer:
Alex_Xolod [135]2 years ago
3 0
Carrot carrot carrot carrot
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If Santa Claus is in the beach then what will you call him?​
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3 years ago
What is the mass of a substance in 0.5 mol of nh3​
KATRIN_1 [288]

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17 g/mol

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6 0
3 years ago
Using the periodic tables, identify the heaviest member of each of the following groups:
Lady_Fox [76]

Answer:

(a) Alkali metals: Francium (Fr)

(b) Chalcogens: Polonium (Po)

(c) Noble gases: Radon (Rn)

(d) Alkaline earth metals: Radium (Ra)

Explanation:

In the periodic table, the atomic mass increases down the group. Therefore, the last element of a group is the heaviest element of the group.

(a) alkali metals: The chemical elements that are present in group 1 of the periodic table, except hydrogen.

<u>The heaviest member of this group is francium (Fr)</u>

(b) chalcogens: The chemical elements that are present in group 16 of the periodic table

<u>The heaviest member of this group is polonium (Po)</u>

(c) noble gases:  The chemical elements that are present in group 18 of the periodic table

<u>The heaviest member of this group is radon (Rn)</u>

(d) alkaline earth metals: The chemical elements that are present in group 2 of the periodic table.

<u>The heaviest member of this group is radium (Ra)</u>

7 0
3 years ago
How many moles are present in 3.4 x 1023 atoms of Na?
Andrej [43]
<h3><u>moles of H2SO4</u></h3>

Avogadro's number (6.022 × 1023) is defined as the number of atoms, molecules, or "units of anything" that are in a mole of that thing. So to find the number of moles in 3.4 x 1023 molecules of H2SO4, divide by 6.022 × 1023 molecules/mole and you get 0.5646 moles but there are only 2 sig figs in the given so we need to round to 2 sig figs. There are 0.56 moles in 3.4 x 1023 molecules of H2SO4

Note the way this works is to make sure the units are going to give us moles. To check, we do division of the units just like we were dividing two fractions:

(molecules of H2SO4) = (molecules of H2SO4)/1 and so we have 3.4 x 1023/6.022 × 1023 [(molecules of H2SO4)/1]/[(molecules of H2SO4)/(moles of H2SO4)]. Now, invert the denominator and multiply:

<h3 />
7 0
2 years ago
If the pOH of a nitric acid (HNO3) solution is measured as 11, what is the concentration of HNO3 solution? Choose one
miss Akunina [59]
PH + pOH = 14

pH
= 14 - pOH
= 14 - 11
= 3

pH = 3
- lg [H+] = 3
[H+]
= 0.001
= [HNO3]
= 1 x 10-3 M
8 0
2 years ago
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