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1 year ago

Starting at sea level, a submarine descended at a constant rate to a depth of −3/4 mile relative to sea level in 5/8 minutes.

Mathematics

1 answer:

zheka24 [161]1 year ago

7 0

The submarine's depth relative to sea level after the first minute is 1.2 miles

<h3>How to find the submarine's depth relative to sea level after the first minute?</h3>

To find the submarine's depth after the first minute, we first need to find the rate at which the submarine descends, r.

The rate at which the submarime descends is r = d/t where

d = submarine's depth and
t = time of descent to depth d.

Given that submarine descended at a constant rate to a depth of −3/4 mile relative to sea level in 5/8 minutes, we have that

d = -3/4 mile and
t = 5/8 minutes.

So, substituting these into r, we have

r = d/t

= -3/4 mile ÷ 5/8 min

= -3/4 × 8/5

= -3 × 2/5

= -6/5

= -1.2 mile/min

So, the depth of the submarine after the first minute is given by D = rt where r = rate of descent = -1.2 mile/min and t = time = 1 min

So, substituting these into D, we have

D = rt

= -1.2 mile/min × 1 min

= -1.2 mile

So, the submarine's depth relative to sea level after the first minute is 1.2 miles

Learn more about submarine's depth here:

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In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

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3 years ago

Aida makes $9.25 per hour. Aida works 14 hours in one week. At the end of the week, Aida deposits 1/5 of her total income into a

Lina20 [59]

Answer:

$103.6 left

Step-by-step explanation:

First, multiply the amount she earns an hour times how many hours she worked:

9.25 x 14 = 129.5

Then divide the total by 1/5:

129.5 / 5 = 25.9

Then subtract that value from the total:

129.5 - 25.9 = 103.6

$103.6 is your answer

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Which shape is both a parallelogoram and a rhombus

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Answer:

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3 years ago

A population of voters contains 40% republicans and 60% democrats. it is reported that30% of the republicans and 70% of the demo

Blizzard [7]

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p (favour) = 0.12 + 0.42 = 0.54

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P (dem & favour) = 0.42 / 0.54 = 0.7778 = 0.78

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