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Arisa [49]
2 years ago
14

How do you solve 20y-15-6y

Mathematics
1 answer:
rosijanka [135]2 years ago
4 0
20y-6y-15

=14y-15 is the answer
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The nicotine content in a single cigarette of a particular brand has a distribution with mean 0.9 mg and standard deviation 0.1
Ad libitum [116K]

Answer:

The answer to the question is;

The probability that the resulting sample mean of nicotine content will be less than 0.89 is 0.1587 or 15.87 %.

Step-by-step explanation:

The mean of the distribution = 0.9 mg

The standard deviation of the sample = 0.1 mg

The size of the sample = 100

The mean of he sample = 0.89

The z score for sample mean is given by

Z =\frac{X-\mu}{\sigma/ \sqrt{n} } where

X = Mean of the sample

μ = Mean of the population

σ = Standard deviation of the population

Therefore Z = \frac{0.89-0.90}{0.1/\sqrt{100} } = -1

From the standard probabilities table we have the probability for  a z value of -1.0 = 0.1587

Therefore the probability that the resulting sample mean will be less than 0.89 = 0.1587 That is the probability that the mean is will be less than 0.89 is 15.87 % probability.

             

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3 years ago
What graph represents the function f(x)= -x2+5?
ololo11 [35]
I hope it would helps

6 0
2 years ago
Simplify the next two expressions
prisoha [69]
1. 7x-40
2. 8x-30y-10
4 0
3 years ago
Jerry sold 7/20 of the toral number of tickets that we're sold for the spring band concert
Juli2301 [7.4K]

Question is Incomplete;Complete question is given below;

Jerry sold 7/20 of the total number of tickets that were sold for the spring band concert. What percent of the total number of tickets did jerry sell.

Answer:

Jerry sold 35 % of the total tickets.

Step-by-step explanation:

Given:

Jerry sold tickets = \frac{7}{20} of total number of tickets

We need to find the percent of the total number of tickets Jerry sold.

Solution:

to find the percent of the total number of tickets Jerry sold we need to multiply the fraction by 100 we get;

framing in equation form we get;

Percent of the total number of tickets Jerry sold = \frac{7}{20}\times100 = 35\%

Hence Jerry sold 35 % of the total tickets.

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3 years ago
-2/x^2-4 + x-1/x^2-2x
Fiesta28 [93]

Answer:

I need help with this too

Step-by-step explanation:

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3 years ago
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