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Paladinen [302]
3 years ago
13

Round each number to the underline place value 3.789 seven being underline

Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

4

Step-by-step explanation:

the 7 is over 5 which makes the 3 round to a 4

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2/7 divided by 1/4 =
dem82 [27]

Answer: 8/7

Step-by-step explanation:

To solve 2/7 ÷ 1/4,

Step 1: rewrite as-

2/7 × 4/1

=8/7

I hope this is clear.

4 0
3 years ago
Find the value of x in the following triangle​
ozzi

Answer:

x = 124°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then

x = 180° - (32 + 24)° = 180° - 56° = 124°

4 0
3 years ago
Show that the line 3y = 7 + 5x is perpendicular to the line 5y = 4 - 3x.
ZanzabumX [31]

Answer:

Proven Below

Step-by-step explanation:

If we rearrange these equations, we get that 3y = 5x + 7 and that 5y = -3x + 4. Next, to find what y equals on both equations, we divide by 3 on both sides of the first equation, where we would get that y = 5/3x + 7/3, and then divide by 5 on both sides of the second equation, where we would get that y = -3/5x + 4/5. Now, to see if two lines are perpendicular to each other, we have to see if the slopes (The number being multiplied by x. Ex.) In the equation y = 3/4x + 4, the slope is 3/4) are opposite reciprocals (If you multiply them and they are equal to -1. Ex.) 3/4 * -4/3 is equal to -1, so they are opposite reciprocals). In this case, we have -3/5 and 5/3 as slopes, and -3/5 * 5/3 is equal to -1, so they are perpendicular.

8 0
3 years ago
Read 2 more answers
Please help equation: x=16-4y
zimovet [89]

Answer:

y= x/4 +4

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

5 0
3 years ago
Please help with this problem. I keep getting -25
katrin [286]
\bf -\sqrt[5]{-(400^2)}\implies -\sqrt[5]{-[(20\cdot 20)^2]}\implies -\sqrt[5]{-[(20^2)^2]}
\\\\\\
-\sqrt[5]{-(20^{2\cdot 2})}\implies -\sqrt[5]{-(20)^4}\implies -\sqrt[5]{-(2^2\cdot 5)^4}
\\\\\\
-\sqrt[5]{-2^{2\cdot 4}\cdot 5^4}\implies -\sqrt[5]{-2^8\cdot 5^4}\implies -\sqrt[5]{-2^{5+3}\cdot 5^4}
\\\\\\
-\sqrt[5]{-2^5\cdot 2^3\cdot 5^4}\implies 2\sqrt[5]{2^3\cdot 5^4}\implies 2\sqrt[5]{5000}
4 0
4 years ago
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