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777dan777 [17]
1 year ago
8

The scores on a statistics test had a mean of 81 and a standard deviation of 9. One student was absent on the test day, and his

score wasn’t included in the calculation. If his score of 84 was added to the distribution of scores, what would happen to the mean and standard deviation?.
Mathematics
1 answer:
Rama09 [41]1 year ago
8 0

Using the definitions of the mean and of the standard deviation of a data-set, we have that:

  • The mean would increase.
  • The standard deviation would remain constant.

<h3>What are the mean and the standard deviation of a data-set?</h3>

  • The mean of a data-set is given by the <u>sum of all values in the data-set, divided by the number of values</u>.
  • The standard deviation of a data-set is given by the <u>square root of the sum of the differences squared between each observation and the mean, divided by the number of values</u>.

When the measure of 84 is added to the data-set, we have that:

  • A measure greater than the mean is added, hence the mean would increase.
  • The difference squared between 84 and the mean of 81 is of 9, which is the same as the standard deviation, which would remain constant.

More can be learned about the mean and the standard deviation of a data-set at brainly.com/question/26941429

#SPJ1

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Answer:

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5 0
3 years ago
wiĺla's rectangular patio has an area of 36m, and whole area side lengths. what might the length and width of the atio be? give
Vinil7 [7]
The length can be 18 and the width can be 2.
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5 0
3 years ago
Ryan has a collection of220 baseball cards.helets his bro have 1/4 of his collection &amp; sells 20% of the coll to the baseball
patriot [66]
So he gives 1/4 to his brother 220/4=55 then then he sells the 20% which is 220*.20=44 and then 15 he takes to his friends so if you add those you get        55+44=99+15=114 then subtract this number from the total 220-114=106
7 0
4 years ago
You have made two of the exact same necklaces that cost you a total of $15 in supplies. You have chosen to mark up the price by
tatyana61 [14]

Answer:

A) The selling price for each necklaces is $8.625

B) The profit mark in each necklaces is 15%

Step-by-step explanation:

Given as :

The total cost of two necklaces = c.p = $15

The markup percentage for the necklaces = m = 15%

Let The selling price for both necklaces = s.p

A ) <u>Now, From markup method</u>

m% = \dfrac{s.p - c.p}{c.p}

or, 15% =  \dfrac{s.p - 15}{15}

or, 15% =  \dfrac{s.p}{15} - 1

or, \dfrac{s.p}{15} = 1 + 15%

or, \dfrac{s.p}{15} = 1 +  \dfrac{15}{100}

or, \dfrac{s.p}{15} =  \dfrac{100 + 15}{100}

or,  \dfrac{s.p}{15} =  \dfrac{115}{100}

∴ s.p = \frac{15\times 115}{100}

I.e s.p = $17.25

So, selling price of two necklaces = s.p = $17.25

or, selling price of one necklaces = s.p = \dfrac{17.25}{2} = $8.625

Hence, The selling price for each necklaces is $8.625

<u>Now, Again</u>

B) ∵ The total cost of two necklaces = c.p = $15

So, The cost price of one necklaces = \dfrac{15}{2} = $7.5

∴ profit% for each necklace =  \dfrac{s.p - c.p}{c.p}

i.e profit% for each necklace =  \dfrac{8.625 - 7.5}{7.5}

Or, profit% for each necklace =  \dfrac{1.125}{7.5}

Or, profit% for each necklace = 0.15

So, The profit make in each necklaces = 15%

Hence, The profit mark in each necklaces is 15%

Answer

8 0
3 years ago
PLEASE HELP I GIVE THANKS
timurjin [86]
The formula for a cylinder's surface area is, as I said before : \\ 2\pi rh+2\pi { r }^{ 2 } in this question, h=x

Let's plug the values and solve :

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7 0
3 years ago
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