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Leto [7]
2 years ago
6

Simplify sec^2x-tan x-3

Mathematics
2 answers:
mrs_skeptik [129]2 years ago
7 0

\huge\longmapsto\mathfrak{Answer}

=》

\sec {}^{2} (x)  - tan(x) - 3

=》

\tan {}^{2} (x)  + 1 -  \tan(x)  - 3

=》

\tan {}^{2} (x)  -  \tan(x)  - 2

=》

\tan {}^{2} (x)  -  2\tan(x)  +  \tan(x)  - 2

=》

\tan(x) ( \tan(x)  - 2) + 1( \tan(x) - 2)

=》

( \tan(x)  + 1)( \tan(x)  - 2)

so,

case - 1

=》

\tan(x)  =  - 1

case - 2

\tan(x)  = 2

zvonat [6]2 years ago
6 0
Sec^2x-tan x-3 = RED IS SUS
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\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})}
\\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}})
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=0\\
k=0\\
p=5
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\\\\\\
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