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Leto [7]
3 years ago
6

Simplify sec^2x-tan x-3

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0

\huge\longmapsto\mathfrak{Answer}

=》

\sec {}^{2} (x)  - tan(x) - 3

=》

\tan {}^{2} (x)  + 1 -  \tan(x)  - 3

=》

\tan {}^{2} (x)  -  \tan(x)  - 2

=》

\tan {}^{2} (x)  -  2\tan(x)  +  \tan(x)  - 2

=》

\tan(x) ( \tan(x)  - 2) + 1( \tan(x) - 2)

=》

( \tan(x)  + 1)( \tan(x)  - 2)

so,

case - 1

=》

\tan(x)  =  - 1

case - 2

\tan(x)  = 2

zvonat [6]3 years ago
6 0
Sec^2x-tan x-3 = RED IS SUS
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What are the first and last terms of this geometric series
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ANSWER

E. 10 and 640


EXPLANATION


The given series is

\sum_{i=1}^45 \times 2^{2i-1}


To find the first term of the series we substitute i=1 to get,


a_1 = 5 \times  {2}^{2 \times 1 - 1}


a_1 = 5 \times  {2}^{ 1}  = 10



For the last term of the series, we substitute i=4 to obtain,

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Therefore the correct answer is E
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