The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
For given question,
We have been given the recursive formula of a sequence.

Also, the first term of the sequence is,
a1 = 6
Substitute k = 1 in given recursive formula.
⇒ 
⇒ a2 = 1/3 (6)²
⇒ a2 = (1/3) × 36
⇒ a2 = 12
Substitute k = 2 in given recursive formula.
⇒ 
⇒ a3 = (1/3) × (12)²
⇒ a3 = (1/3) × 144
⇒ a3 = 48
Substitute k = 3 in given recursive formula.
⇒ 
⇒ a4 = (1/3) × (48)²
⇒ a4 = (1/3) × 2304
⇒ a4 = 768
Substitute k = 4 in given recursive formula.
⇒ 
⇒ a5 = (1/3) × (768)²
⇒ a5 = (1/3) × 589824
⇒ a5 = 196608
Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
Learn more about the recursive formula of sequence here:
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There will be around 280 phones defective
Around 720 elk will be infected
Answer:
A = 28.3
Step-by-step explanation:
R = d/2
R = 6/2
R = 3
A = πr^[2]
A = (3.14) x (3^[2])
A = 3.14 x 9
A = 28.26
Rounded to the nearest tenth is 28.3
Answer:
constant term is -3, the leading term is 3x^3, the coefficient is 3.
Step-by-step explanation:
Answer:
147/99
Step-by-step explanation:
(1.48 x 100) - 1 99