we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx
so
we have
a) for x=1 y=0.50--------> y/x=0.50/1------> 0.50
b) for x=2 y=1--------> y/x=1/2-------> 0.50
c) for x=3 y=1.50--------> y/x=1.50/3-----> 0.50
d) for x=5 y=2.50--------> y/x=2.50/5----> 0.50
the value of k is equal to 0.50
so
<span>the relationship forms a direct variation. </span>
the equation is
y=0.50*x
Verify
for x=1
y=0.50*(1)------> y=0.50-----> is correct
for x=2
y=0.50*(2)------> y=1.00-----> is correct
for x=3
y=0.50*(3)------> y=1.50-----> is correct
for x=5
y=0.50*(5)------> y=2.50-----> is correct
Answer:33
Step-by-step explanation: took one for the team
Answer:
4800m³
Step-by-step explanation:
V=
=
=4800
Answer:
Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is
13x - 4y = 84.
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( 4 ,-8)
point B( x₂ , y₂) ≡ (8 , 5)
To Find:
Equation of Line AB =?
Solution:
Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

Substituting the given values in a above equation we get

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is
13x - 4y = 84.
Answer:
<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>
<h2 />
<h2>here your answer </h2>