The standard deduction compare to Chris’s deductions is letter D which is "<span>The standard deduction is $664 better than Chris’s deductions."
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Answer:
DEF = 110
Step-by-step explanation:
Supplementary angles add to 180
3x+5 +2x = 180
Combine like terms
5x +5 = 180
Subtract 5 from each side
5x = 175
Divide each side by 5
5x/5 = 175/5
x =35
DEF = 3x+5
= 3*35 +5
= 105+5
= 110
Answer:
Choice B
Step-by-step explanation:
Given radical expression:
![\sqrt[4]{1296 {x}^{16} {y}^{12} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1296%20%7Bx%7D%5E%7B16%7D%20%20%7By%7D%5E%7B12%7D%20%7D%20)
To Find:
The Simpler form of this expression
Soln:
![= \sqrt[4]{1296 {x}^{16} {y}^{12} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%5B4%5D%7B1296%20%7Bx%7D%5E%7B16%7D%20%20%7By%7D%5E%7B12%7D%20%7D%20)
We could re-write the given expression, according to the law of exponents:
![= \tt \sqrt[4]{(6x {}^{4}y {}^{3}) {}^{4} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Ctt%20%5Csqrt%5B4%5D%7B%286x%20%7B%7D%5E%7B4%7Dy%20%7B%7D%5E%7B3%7D%29%20%20%7B%7D%5E%7B4%7D%20%20%7D%20)
Now we need to bring terms out of the radical as:

Bring out 6x^4 from the absolute & put y^3 only in it:

Choice B is accurate.
A square has four sides. Hope this helps you.
First set up a linear equation and using the x and y values in the table see if it solves.
It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)
Using the quadratic formula y = ax^2 +bx +c
Build a set of 3 equations from the table:
C is the Y intercept ( when X is 0), this is shown in the table as 6
Now we have y = ax^2 + bx + 6
-2.4 =4a-2b +6
1.4 = a-b +6
Rewrite the equations
a=b/2 -2.1
1.4 = b/2-2.1 +6
b = 5
a = 5/2 -2.1 = 0.4
replace the letters to get y = 0.4x^2 + 5x +6