The probability distribution for a

Sahana sells two products for ₹. 8000 each gaining 8% on one and losing 6% on the other. Find her gain or loss percent in the wh

Margaret [11]

Based on the information given the gain or loss percent on the whole transaction is 1%.

<h3>Gain or loss percent: </h3>

First step is to calculate the profit on the whole transaction

Profit=(8%×8,000)-(6%×8,000)

Profit=$640-$480

Profit=$160

Now let calculate the gain or loss percentage on the whole transaction

Gain or loss percentage=160/(8000+8000)×100

Gain or loss percentage=160/16000×100

Gain or loss percentage=1%

Inconclusion the gain or loss percent on the whole transaction is 1%.

Learn more about gain or loss here:brainly.com/question/25278228

5 0

2 years ago

At breakfast, restaurant charges $2 for the first cup of orange juice and then $1 for each refill which graph represents this si

liq [111]

Answer:

line

Step-by-step explanation:

y= 2+(x-1)*1= x+1

y=x+1

linear function, the graph is going to be a line

6 0

3 years ago

Read 2 more answers

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

Can someone help me with this problem?

coldgirl [10]

Answer:

147

Step-by-step explanation:

add the 2 sides together 19+14=33 then take 33 and subtract from 180. bc thats the rule btw. So 180-33= 147 hope this helps :))

5 0

3 years ago

Shoe size and grade point average

sergey [27]

Answer:

Mild correlation.

Step-by-step explanation:

Girls tend to have smaller feet and so smaller shoe sizes and they tend to score better at school.

7 0

3 years ago