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defon
1 year ago
6

Simplify: 11y-110/50-5y

Mathematics
1 answer:
alexandr1967 [171]1 year ago
7 0
<h2>Answer:</h2>\frac{11y-110}{50-5y}=-\frac{11}{5}

<h2>Explanations:</h2>

Given the following expression show below;

\frac{11y-110}{50-5y}

Factor out the GCF from both the numerator and denominator

\frac{11(y-10)}{5(10-y)}

This can also be expressed as;

\begin{gathered} \frac{11(-10+y)}{5(10-y)} \\ \frac{-11(10-y)}{5(10-y)} \end{gathered}

Cancel out the common expression

\frac{-11\cancel{(10-y)}}{5\cancel{(10-y)}}=-\frac{11}{5}

Hence the simplified form of the expression is -11/5

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(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

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Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

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Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

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Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

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Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

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