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nadezda [96]
1 year ago
11

43 pointThe length of a rectangular box is 5 inches longer than twice the width (x).The height is 6 inches.Which is the volume (

y) when the width (x) is 9 inches

Mathematics
1 answer:
inna [77]1 year ago
3 0
\begin{gathered} V=\text{ w}\cdot L\cdot h \\ V=9in\cdot(23in)\cdot6in=1242in^3 \end{gathered}

L = 2*9+5=23

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Studies show that a typical giant hummingbird can flap its wings once in 0.08 of a second.
Licemer1 [7]

Answer:

a. 90

b. 360

Step-by-step explanation:

The time taken by humming bird to flap its wings= 0.08 sec

by flying 7.2 seconds a typical giant hummingbird flap its wings \frac{7.2}{0.08} times

= 90 times

Since, A ruby-throated hummingbird can flap its wings 4 times faster than a giant hummingbird, it will flap its wings in every 0.02 sec

so in 7.2 seconds it will flap \frac{7.2}{0.02} times = 360 times

4 0
3 years ago
What is the address of the element 14 in Matrix D
MAXImum [283]

Answer:

A.)D23

Step-by-step explanation:


6 0
4 years ago
Read 2 more answers
Is (0,5) a solution to the equation y=2x?​
klio [65]

Answer:

No.

Step-by-step explanation:

If (0,5) is a solution to y=2x, then 5=2(0) has to be true.

It is not because 5=2(0) is not true.

2(0)=0 and 0 is definitely not 5.

An example of a point on y=2x is (5,10) since 10=2(5) is true.

3 0
3 years ago
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let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0
1 year ago
Only number 6. ‍ ‍ ‍ ‍ ‍ ‍ ‍
djverab [1.8K]
The answer is 6, 4 divided by 2/3 =6
if you need to show your work just multiply by the reciprocal :)
6 0
3 years ago
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