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geniusboy [140]
3 years ago
9

Бу^5 + 4 y^4 - 3у^3-1 by (3 y^2 - y+1​

Mathematics
1 answer:
Lostsunrise [7]3 years ago
4 0

Answer:

2y^3 + 2y^2 - y - 1

Step-by-step explanation:

6у^5 + 4y^4 - 3у^3-1 by  y^2 - y + 1:-

We need to write the first expression as

бу^5 + 4y^4 - 3у^3 + 0y^2 + 0y  - 1  (inserting all the missing degrees).

So we have:

3y^2 - y + 1​  ) бу^5 + 4y^4 - 3у^3 + 0y^2 + 0y  - 1 ( 2y^3 + 2y^2 - y - 1

                     6y^5  - 2y^4 + 2y^3

                                 6y^4  - 5y^3  + 0y^2

                                 6y^4 - 2y^3  + 2y^2

                                           -3y^3   - 3y^2 + 0y

                                            -3y^3   + y^2  -  y

                                                          - 3y^2 + y  -  1

                                                          - 3y^2  + y -  1

                                                          .........................

         

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