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geniusboy [140]
3 years ago
9

Бу^5 + 4 y^4 - 3у^3-1 by (3 y^2 - y+1​

Mathematics
1 answer:
Lostsunrise [7]3 years ago
4 0

Answer:

2y^3 + 2y^2 - y - 1

Step-by-step explanation:

6у^5 + 4y^4 - 3у^3-1 by  y^2 - y + 1:-

We need to write the first expression as

бу^5 + 4y^4 - 3у^3 + 0y^2 + 0y  - 1  (inserting all the missing degrees).

So we have:

3y^2 - y + 1​  ) бу^5 + 4y^4 - 3у^3 + 0y^2 + 0y  - 1 ( 2y^3 + 2y^2 - y - 1

                     6y^5  - 2y^4 + 2y^3

                                 6y^4  - 5y^3  + 0y^2

                                 6y^4 - 2y^3  + 2y^2

                                           -3y^3   - 3y^2 + 0y

                                            -3y^3   + y^2  -  y

                                                          - 3y^2 + y  -  1

                                                          - 3y^2  + y -  1

                                                          .........................

         

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Step-by-step explanation:

Example 1

Solve the equation x3 − 3x2 – 2x + 4 = 0

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

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Example 2

We can easily use the same method to solve a fourth degree equation or equations of a still higher degree. Solve the equation f(x) = x4 − x3 − 5x2 + 3x + 2 = 0.

First we find the integer factors of the constant term, 2. The integer factors of 2 are ±1 and ±2.

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