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Serhud [2]
1 year ago
12

I need help with this practice problem It’s from my trig prep guide

Mathematics
1 answer:
Zinaida [17]1 year ago
6 0

We know that π = 180°, therefore:

1.

2\pi=2(180)=360

Answer: correct

2.

\frac{5\pi}{6}=\frac{5(180)}{6}=\frac{900}{6}=150

Answer: no correct

3.

\frac{\pi}{6}=\frac{180}{6}=30

Answer: no correct

4.

\frac{5\pi}{4}=\frac{5(180)}{4}=\frac{900}{4}=225

Answer: correct

5.

\frac{4\pi}{3}=\frac{4(180)}{3}=\frac{720}{3}=240

Answer: correct

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Write the expression as a single fraction:<br> please help, giving brainliest :)
nignag [31]

Answer:

\frac{4a^{2} + 15b}{10ab}

Step-by-step explanation:

find the least common denominator for both fractions then combine them to find:

\frac{4a^{2} + 15b}{10ab}

4 0
3 years ago
How do you make a stem and leaf plot?
Maru [420]

Answer:

How to Make a Stem-and-Leaf Plot

Step 1: Determine the smallest and largest number in the data. The game stats: ...

Step 2: Identify the stems. For any number, the digit to the left of the right-most digit is a stem. ...

Step 3: Draw a vertical line and list the stem numbers to the left of the line.

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Step-by-step explanation:

6 0
3 years ago
HELPPPP<br><br> If y=4, 3y+6=7(2y-3)
Step2247 [10]

Answer:

i think your question is missing something??

Step-by-step explanation:

3(4) + 6 = 7 (2(4)-3)

12 + 6 = 7 (8-3)

18 = 7 (5)

18 = 35?

8 0
3 years ago
(W+4)(3w-2) please solveeed
Shkiper50 [21]

Step-by-step explanation:

{:}\longrightarrow\sf (w+4)(3w-2)

{:}\longrightarrow\sf w(3w-2)+4 (3w-2)

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{:}\longrightarrow\sf 3w^2+10w-8

7 0
3 years ago
Read 2 more answers
Assume a normal distribution and that the average phone call in a certain town lasted 4 min, with a standard deviation of 1 min.
olya-2409 [2.1K]

SOLUTION

The mean is 4min

standard deviation is 1min

the z score is

z=\frac{x-\bar{x}}{\sigma}

where

\begin{gathered} x=3 \\ \bar{x}=4 \\ \sigma=1 \end{gathered}

then we have

\begin{gathered} z=\frac{3-4}{1}=\frac{-1}{1}=-1 \\ z=-1 \end{gathered}

The probability the call lasted less than 3 min will be

Therefore, the probability that (z < -1 ) is

[tex]\begin{gathered} Pr(z<-1)=Pr(0Hence, the percentage of the calls that lasted less than 3 min is 16%

4 0
1 year ago
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