Total number of team in starting = 128 teams.
In each round half of the teams are eliminated.
Therefore, number of teams remain after first round = 128/2 = 64.
The number of teams remain after second round = 64/2 = 32.
The number of teams remain after third round = 32/2 = 16.
The number of teams remain after fourth round = 16/2 = 8.
The number of teams remain after fifth round = 8/2 = 4.
<h3>Therefore, after 5 rounds there remain only 4 teams.</h3>
Answer:

Explanation:
There are only two mutually exclusive possibilities for each complex electronic system: being <em>defective</em> or being <em>not defective</em>:
- Number of complex electronic systems: 7
- Nmber of defective systems: 2
- Number of not defective systems: 5
<em>Probability </em>that no defective systems are found in the sample is the equal to the probability of selecting them consecutively without replacement and finding each one is not defective:
- Porbability the first is not defective × probability the second is not defective
- 5/7 × 4/6 = 20/42 = 10/21
Answer:
Pythagorean Theorem:
a^2 + b^2 = c^2
6^2 + b^2 = 12^2
36 + b^2 = 144
b^2 = 108
b = 10.4
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Answer:
what is the step by step of 1/ cos x csc^2 x = sin x/ cot x
Step-by-step explanation:
1
.
csc
x
=
1
sin
x
2
.
cot
x
=
cos
x
sin
x
Given,
1
−
cos
x
sin
x
=
csc
x
−
cot
x
Simplify the right side.
csc
x
−
cot
x
=
1
sin
x
−
cos
x
sin
x
=
1
−
cos
x
sin
x
∴
, LS
=
RS.