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8_murik_8 [283]
1 year ago
11

What is the range of the relation[(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)]

Mathematics
1 answer:
vesna_86 [32]1 year ago
4 0

The range is the set of values that the relation takes for the domain for which it is defined.

Is the set of values of the dependent variable.

In this case, we have the relation [(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)]​.

The dependant variable takes the values: 0, -3, 4, 0 and -1. Some values are repeated.

We put the repeated values only once and sort to write the range.

Then, the range is R = {-3, -1, 0, 4}.

Answer: Range = {-3, -1, 0, 4}

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The first step is to find the CHANGE. This is done by subtracting the two values and taking the absolute value. Next step is to find the ratio of the change to the original and multiplying by 100% to make it a percentage.

So;

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     ratio of change to original = 35:25,

    multiplying by 100% will give 35/25 × 100% = 140%.

    Hence it is a 140% INCREASE.

b) change = | 30 - 66 | = 36

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multiplying by 100% = 36/66 × 100% = 0.545454... ×100% ≈ 54.5%

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Helpful?

     



4 0
3 years ago
Make a table for each function rule. Then graph each equation using the points you created.
aleksandrvk [35]

Answer:

1.f(x)=2x-5

i will take the set {-2,-1,0,1,2}

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=-2-5

=-7

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f(1)=2(1)-5

=-3

f(2)=2(2)-5

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so the coordinates of the function is {-9,-7,-5,-3,-1}

2.f(x)=-3x+6

i will the take the set {-2,-1,0,1,2} too

f(-2)=-3(-2)+6=6+6=12

f(-1)=-3(-1)+6=3+6=9

f(0)=-3(0)+6=6

f(1)=-3(1)+6=-3+6=3

f(2)=-3(2)+6=-6+6=0

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3.f(x)=2/3.x+4

{-2,-1,0,1,2}

f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3

f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3

f(0)=2/3(0)+4=4

f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3

f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3

{8/3,10/3,4,14/3,16/3}

you're can graph those coordinates

actually you can take other coordinates...

CMIIW

,

7 0
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irga5000 [103]
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Answer:

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Step-by-step explanation:

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