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8_murik_8 [283]
1 year ago
11

What is the range of the relation[(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)]

Mathematics
1 answer:
vesna_86 [32]1 year ago
4 0

The range is the set of values that the relation takes for the domain for which it is defined.

Is the set of values of the dependent variable.

In this case, we have the relation [(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)]​.

The dependant variable takes the values: 0, -3, 4, 0 and -1. Some values are repeated.

We put the repeated values only once and sort to write the range.

Then, the range is R = {-3, -1, 0, 4}.

Answer: Range = {-3, -1, 0, 4}

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Answer:

t(g)= -4g + 20

Step-by-step explanation:

James is playing his favorite game at the arcade. After playing the game 3 times, he has 8 tokens remaining. He initially had 20 tokens, and the game costs the same number of tokens each time. The number tt of tokens James has is a function of gg, the number of games he plays

Solution

Let

g=No. of games James plays

t= No. of tokens James has.

Find the slope using

y=mx + b

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b = y-intercept.

Before James started playing the games, he has a total of 20 tokens.

That is, when g=0, t=20

After James played the games 3 times, he has 8 tokens left

That is, when g=3, t=8

(x,y)

(0,20) (3,8)

m=y2-y1 / x2-x1

=(8-20) / (3-0)

= -12 / 3

m= -4

Slope of the line, m= -4

y=mx + b

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List the sides in order from shortest to longest j=33 k=71 l=76
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Which is the line shown in the figure?
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Answer:

\mathbf{r^{\to} (t) = ti^{\to} + 5t^2^{\to} j+(6t^2 + 25t^4) k ^{\to}}

Step-by-step explanation:

Given that:

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Let assume that:

x = t

then from y = 5x², we have:

y = 5t²

Now replace y = 5t² and x = t into z = 6x² + y²

z = 6t² + (5t²)²

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As a vector equation:

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