Answer: 10 squares.
Step-by-step explanation:
We can do it with integrals.
If we take the bottom vertex as the point (0,0), the top right vertex as the point (0,4) and the left vertex as the point (5, 6)
then the area of the triangle is the area enclosed by two lines between the values x = 0 and x = 5.
the two lines are:
the bottom is the one that passes through (0,0) and (5,6)
f(x) = y = s*x (because it passes through the point (0,0))
and the slope is s = 6/5.
so f(x) = y = (6/5)*x.
The top line is the one that passes through (0,4) and (5,6)
the y-intercept is b = 4, and the slope is:
s = (6 - 4)/(5 - 0) = 2/5.
g(x) = y = (2/5)*x + 4.
Now, the area enclosed for the triangle is equal to:

this is equal to:

= (1/2)(-4/5)*(5)^2 + 4*5 - 0 = 10
The area is 10 squares
The inequality would be 200>(or equal to) 500-25x, x representing the number of weeks. Then you just solve the inequality. Subtract 500 from both sides (-300= -25x). Divide both sides by -25 (12=x). The answer is he can withdraw money for up to 12 weeks.
The answer is C.
<span>The set has 50 as an outlier and removing it increases the mean by about 3.
Since 50 is significantly smaller number than all others, it is expected that removing 50 will increase the mean.
The first mean is 76:
</span>

<span>
The mean after removing 50 is:
</span>

X₂ ≈ 79<span>
</span>
The difference between the second and the first mean is 79 - 76 = 3, thus
<span>removing 50 as an outlier increases the mean by about 3.</span>
what do we do??? im not understanding the question..lol