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2 years ago

A² + 11a + 30 Plsss help

Mathematics

1 answer:

Debora [2.8K]2 years ago

5 0

Answer:

( a + 5 ) ( a + 6 )

? maybe

Step-by-step explanation:

I really don't know how to explain

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What do all simple machines have in common?

Arisa [49]

Answer:

D: All of the above.

Step-by-step explanation:

A. All simple machines are useful in some way, weather that be making it easier to lift heavy objects, activating other machines, or something else.

B. Any simple machine must be, well, simple. i. e. have few moving parts.

Take the lever, for example. It has only one moving part, yet it is still very useful.

C. They can be used to do work. Simple machines can be put together to make something that can do work.

Imagine a windmill that generates power, which then is taken by a motor attached to an Archimedes screw. All of these machines are simple, yet they are still used to do work.

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3 years ago

Using only addition, how can you add eight 8’s to get the number 1,000?

FinnZ [79.3K]

Answer:

888+88+8+8+8

Step-by-step explanation:

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3 years ago

What number must you add to complete the square?

Travka [436]

B=9 (x+3)^2= x^2+6x+9

7 0

3 years ago

Consider this equation. Cos(0) = 8/9 if 0 is an angle in quadrant IV, what is the value of tan(0)? I

Vinvika [58]

Answer:

$\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}$

Step-by-step explanation:

We are given that:

$\displaystyle \cos(\theta)=\frac{8}{9}$

Where θ is in QIV.

And we want to find the value of tan(θ).

Recall that cosine is the ratio of the adjacent side over the hypotenuse.

Therefore, the opposite side is:

$o=\sqrt{9^2-8^2}=\sqrt{17}$

Next, in QIV, only cosine is positive: sine and tangent are both negative.

Tangent is the ratio of the opposite side to the adjacent. So:

$\displaystyle \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}$

Substitute. Tangent is negative in QIV. Hence:

$\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}$

3 0

3 years ago

One number is 4 times another number. The sum of their reciprocals is 5. What are the two numbers?

ivann1987 [24]

Answer:

The two number are:

$y=1,\:x=\frac{1}{4}$

Step-by-step explanation:

Let 'x' be the first number

let 'y' be the second number

Given that one number is 4 times another number, the first equation is

$y = 4x$

Next, the sum of their reciprocals is 5, so

$\frac{1}{x}+\frac{1}{y}=5$

Now, we have the system of equations

$\begin{bmatrix}y=4x\\ \frac{1}{x}+\frac{1}{y}=5\end{bmatrix}$

Let us solve the system of equations

$\begin{bmatrix}y=4x\\ \frac{1}{x}+\frac{1}{y}=5\end{bmatrix}$

substitute y = 4x in the equation $\frac{1}{x}+\frac{1}{y}=5$

$\frac{1}{x}+\frac{1}{4x}=5$

Least Common Multiple of x, 4x: 4x

Adjust fractions based on L.C.M

$\frac{4}{4x}+\frac{1}{4x}=5$

$\frac{4+1}{4x}=5$

$\:\frac{5}{4x}=5$

Multiply both sides by 4x

$\frac{5}{4x}\cdot \:4x=5\cdot \:4x$

Simplify

$5=20x$

switch sides

$20x=5$

Divide both sides by 20

$\frac{20x}{20}=\frac{5}{20}$

Simplify

$x=\frac{1}{4}$

For y = 4x, substitute $x=\frac{1}{4}$

$y = 4x$

$y=4\cdot \frac{1}{4}$

$y=1$

Therefore, the two number are:

$y=1,\:x=\frac{1}{4}$

<u>Verification:</u>

$\frac{1}{x}+\frac{1}{y}=5$

substituting $y=1,\:x=\frac{1}{4}$

$\:\frac{1}{\frac{1}{4}}+\frac{1}{1}=\:5\:\:$

$4+1=5$

$5 = 5$

L.H.S = R.H.S

and

$y = 4x$

substituting $y=1,\:x=\frac{1}{4}$

$y\:=\:4\left(\frac{1}{4}\right)$

$y=1$

8 0

3 years ago