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KengaRu [80]
3 years ago
8

Choose the missing step in the given solution to the inequality -2x-14>-4+3x

Mathematics
2 answers:
Komok [63]3 years ago
6 0

Answer:

x

Step-by-step explanation:

The given inequality is

-2x-14>-4+3x

We need to solve the above inequality.

Step 1: Given inequality.

-2x-14>-4+3x

Step 2: Add 14 on both sides.

-2x-14+14>-4+3x+14

-2x>10+3x

Step 3: Subtract 3x from both sides.

-2x-3x>10+3x-3x

-5x>10

Step 4: Divide both sides by -5. If an inequality is multiplied or divided by a negative number then the sign of inequality will change.

\frac{-5x}{-5}  

x

Therefore, the solution of given inequality is x.

madreJ [45]3 years ago
4 0

Answer:

x \in (-\infty, -2)            

Step-by-step explanation:

We have to find the solution of the given inequality.

-2x - 14 > -4 + 3x

The following steps can be followed to find the solution of the given inequality:

-2x - 14 > -4 + 3x\\-2x -3x-14 > -4 +3x-3x\\-5x -14 > -4\\-5x -14 +14 > -4 + 14\\-5x > 10\\x < -2\\\text{In interval notation, we can write}\\x \in (-\infty, -2)

x < -2 is the solution of the given inequality.

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HACTEHA [7]

<u>We'll assume the quadratic equation has real coefficients</u>

Answer:

<em>The other solution is x=1-8</em><em>i</em><em>.</em>

Step-by-step explanation:

<u>The Complex Conjugate Root Theorem</u>

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The question does not specify if the quadratic equation has real coefficients, but we will assume that.

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Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s
AleksAgata [21]

Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

cot(A)=\frac{21}{20}

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