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Gelneren [198K]
1 year ago
14

The table shows the proportional relationship between the price for a certain number of buckets of golf balls at a driving range

.
hurry pls
Buckets 3 5 7
Price (dollars) 28.50 47.50 66.50


Determine the constant of proportionality.
Mathematics
1 answer:
Arte-miy333 [17]1 year ago
5 0

The constant of proportionality will be 9.5 when the table displays the proportionate cost for a particular quantity of golf ball buckets at a driving range.

Given that,

The table displays the proportionate cost for a particular quantity of golf ball buckets at a driving range.

We have to find the constant of proportionality.

We know that,

<h3>What are ratio and proportion?</h3>

A collection of consecutively ordered numbers a and b expressed as a/b, where b is never equal to zero, is referred to as a ratio. A statement is considered proportionate when there is equality between two items.

The table displays the proportional relationship between the price for a particular quantity of golf ball cans at a driving range.

Buckets                         3               5             7

Price (dollars)            28.50       47.50      66.50

The constant of proportionality is calculated as,

⇒ 25.8 / 3

⇒ 9.5

Therefore, The constant of proportionality will be 9.5 when the table displays the proportionate cost for a particular quantity of golf ball buckets at a driving range.

To learn more about proportionality visit: brainly.com/question/22620356

#SPJ1

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Answer:

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Now we just take square root on both sides of the interval and we got:

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The confidence interval for the population variance is given by the following formula:

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s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}&#10;And in order to find the sample mean we just need to use this formula:&#10;[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

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The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

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And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

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