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sergij07 [2.7K]
2 years ago
3

Solve the system of linear equations by substitution. y = -2x - 9 Equation 6x - 5y = -19 Equation 2

Mathematics
1 answer:
dem82 [27]2 years ago
4 0

Solving by substitution method.

We have 2 equations:

y=-2x-9

and

6x-5y=-19

If we substitute the first equation into the second one, we get

6x-5(-2x-9)=-19

which gives

\begin{gathered} 6x-5(-2x)-5(-9)=-19 \\ 6x+10x+45=-19 \\ 6x+45=-19 \\ 6x=-19-45 \\ 6x=-64 \\ x=-\frac{64}{6} \\ x=-10.666 \end{gathered}

Now, we can substitute this result into the first equation, then we get

y=-2(-10.66)-9

then, we have

\begin{gathered} y=21.33-9 \\ y=12.33 \end{gathered}

Therefore, the solution of the system is

\begin{gathered} x=-10.66 \\ \text{and} \\ y=12.33 \end{gathered}

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(I’ll give brainliest)
OLga [1]

Answer:

85.5 miles

Step-by-step explanation:

From the attached diagram, distance between the two rest stops :

Rest stop A to Rest stop B = 2 1/4 inches

Scale factor :

1 in = 38 miles

Acrual distance would be :

2 1/4 inches would be :

2 1/4 * 38 miles

9/4 * 38 = 85.5 miles

6 0
3 years ago
In the expansion of ( x^3 - 2/x^2 ) ^10 , find the coefficient of 1/x^5​
Lilit [14]

Answer:

240

Step-by-step explanation:

We need to find the coeffeicent of the binomial expansion of

( {x}^{3}  - 2 {x}^{ - 2} ) {}^{10}

Note that

- 2 {x}^{ - 2}  = -  \frac{2}{ {x}^{2} }

The binomial theorem states that

(x + y) {}^{n}  = x {}^{n} y {}^{0}  +  \binom{n}{1} x {}^{n - 1} y +  \binom{n}{2} x {}^{n - 2} y {}^{2} ....... + x {}^{0} y {}^{n} ( \binom{n}{n} )

Using this, we let expand our series

( {x}^{3}   - 2 {x}^{ - 2} ) {}^{10}  = x {}^{30}  +  \binom{10}{1} ( {x}^{27}     2 {x}^{ - 2} ) +  \binom{10}{2}  {x}^{24} 2x {}^{ - 4}  +  \binom{10}{3}  {x}^{21} 2x {}^{ - 6}  +  \binom{10}{4}  {x}^{18} 2x { }^{ - 8}  +  \binom{10}{5} x {}^{15} 2x {}^{ - 10}  +  \binom{10}{6} x {}^{12}2 x {}^{ - 12}  +  \binom{10}{7} x {}^{ 9} 2x {}^{ - 14}  +  \binom{10}{8} x {}^{ 6} 2x {}^{ - 16}  +  \binom{10}{9} ( {x}^{3} )2x {}^{ - 18}  + 2x {}^{ - 20}

\frac{1}{ {x}^{5} }  = x {}^{ - 5}

So what term in the series eqaul x^-5.

That term is the 10 choose 7 term.

\binom{10}{7}  {x}^{9} 2x {}^{ - 14}

Because

=  \binom{10}{7} 2x {}^{ - 14}  {x}^{9}  =  \binom{10}{7} 2 {x}^{ - 5}

So we need to compute 10 choose 7.

That equals

10!/3!(7!)= 10×9×8/6= 720/6=120.

So we get

120(2) {x}^{ - 5}

240 {x}^{ - 5}

So the coeffceint u

is 240

3 0
3 years ago
Please I really need help with this question!!!!!
Nina [5.8K]

<u>To solve this problem, we must consider all the trigonometric equations</u>:

 ⇒ (<em>see image below)</em>

<u>Let's examine the diagram</u>:

  • the side adjacent to ∠A ⇒ AC ⇒ 35 meters
  • hypotenuse ⇒ 53 meters

<u>Thus we can use:</u>

 cos(A)=\frac{35}{53} \\A= cos^{-1}(\frac{35}{53})\\ A = 48.67

<u>Answer: 49 degrees</u> <em>(as rounded)</em>

Hope that helps!

3 0
3 years ago
I thought of a two-digit number. The unit digit of my number is 7 more than the tens digit cubed. What is my number?
konstantin123 [22]

9514 1404 393

Answer:

  18

Step-by-step explanation:

Only 1 and 2 will have single-digit cubes. Only 1^3 will still be a single digit after 7 is added. The tens digit must be 1, and the units digit must be 1+7=8.

The number is 18.

7 0
3 years ago
Write an expression to represent how to calculate the area of a triangular sail.
shutvik [7]

Answer:

(b × h) ÷ 2

Step-by-step explanation:

4 0
3 years ago
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