F(x)=x2+5x-1 is shifted 3 units left the result is g(x) what is g(x)?
1 answer:
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Answer:
- 25000 seats in section A
- 14100 seats in sectin B
- 10900 seats in section C
Step-by-step explanation:
The problem statement tells you half the total number of seats are in section A, so you already know that there are 25000 A seats. The revenue from those seats is
... 25000×$25 = $625,000
so the revenue from B and C seats must total
... $1,070,500 - 625,000 = $445,500
If all 25000 of the B/C seats were C seats, the revenue would be
... 25000×$15 = $375,000
The actual revenue from those seats is $445,500 -375,000 = $70,500 more than that. We know each B seat generates $5 more revenue, so there must be ...
... $70,500/$5 = 14,100 . . . . B seats
Then the balance of the 25000 B and C seats are C seats:
... 25,000 - 14,100 = 10,900 . . . . C seats
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<em>Alternate Solution Method</em>
The new Brainly answer format requires the answer be supplied before the working. In order to find the answer quickly so that I can fill in that section, I used a matrix method for solving the problem. The problem equations can be written ...
- a + b + c = 50000
- a - b - c = 0
- 25a + 20b + 15c = 1070500
so the augmented matrix is ...
A graphing calculator can be used to find the solution to this, generally using a function that produces the reduced row-echelon form. The attachment shows the solution using a TI-84 calculator.
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<em>Comment on the Working</em>
Since the number of A seats is equal to the total of B and C seats, the number of A seats must be half the total number of stadium seats. Having figured that out, the problem is reduced to one of finding the mix of B and C seats that will produce the remaining revenue.
As with many mixture problems, it is convenient to look at differences. Start with the assumption that all of the desired revenue comes from the least contributor. Here, that is C seats. Then figure the difference that using a B seat makes ($20 -15 = $5) and the difference of the actual revenue and the amount that you got by assuming all C seats: 445,500 -375,000 = 70,500. Since replacing a C seat by a B seat adds $5 to the revenue, it is easy to figure the number of such replacements required in order to raise the revenue by $70,500.
If you write the equation for B seats, you find the solution to the equation mirrors this verbal description:
... 20b + 15(25000-b) = 445,500
... 5b = 445,500 - 375000 . . . . simplify, subtract 375000
... b = 70500/5 = 14100
Answer:
Ok, primero, como lo deducimos gráficamente?
Sigamos estos pasos.
Dibujemos en una recta, la distancia entre el punto 0 soles y el precio de la bicicleta = 200 soles.
200 soles representa el 100%.
Ella lo quiere vender al 80% (o le quiere restar el 20%).
Entonces, con una regla, medir la distancia entre 0 soles y 200 soles.
Dividir esa cantidad por 10. (cada una de estas cantidades va a representar un 10%)
Multiplicar eso por 8.
Esa cantidad es el equivalente al 80% del precio de la bicicleta.
Abajo hay un dibujo donde se ve el método.
Una forma mas matemática de resolverlo es:
200 soles = 100%.
x soles = 80%
x es el precio al que ella va a vender la bicicleta:
Veamos el cociente de esas dos ecuaciones:
200/x = 100%/80%
x = 200*(80%/100%) = 160
Ella vendería la bicicleta en 160 soles.
