Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
alternate exterior means outside of the two parallel lines so your answer is 7 because alternate means other side of transversal
The decimal of the fraction 2/7 is 0.2857142857
Ans
184 sq meter
Step-by-step explanation:
Area of the cuboid box = (2*FA)+(2*SA)+(2*TA)
Where FA= Front face area
SA= Side face area
TA= top face are
Here FA= length * breadth = 10*6=60 sq meter
SA= 10*2= 20 sq meter
TA= 6*2= 12 sq meter
So area of box= 2*60+2*20+2*12= 184 sq meter
Answer:
see explanation
Step-by-step explanation:
The meaning of n factorial → n !
n ! = n(n - 1)(n - 2)........ × 3 × 2 × 1
For example
7 !
= 7 × 6 × 5 × 4 × 3 × 2 × 1
