Question

I need some help please out

Answer 1

Question:

Solution:

Let the following equation:

$\sqrt[]{12-x}=\text{ x}$

this is equivalent to:

$(\sqrt[]{12-x})^2=x^2$

this is equivalent to:

$12-x=x^2$

this is equivalent to:

$x^2+x-12=\text{ 0}$

thus, we can conclude that

x= 3.