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2 years ago

1. In Mrs. Fields science class, the ratio of girls to boys is 5 to 3. If the

Mathematics

1 answer:

victus00 [196]2 years ago

7 0

Answer:

Step-by-step explanation:

i thinkk

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elizabeth made an english muffin pizza using 1/4 cup of cheese and 3/8 cup of sasuage how many cups of toppings did she use

suter [353]

14 cups and 2cent and u will need to times the sausages by 55 to get the prime factorization

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2 years ago

Read 2 more answers

Is 14 200 000 in scientific notation 1.42 10x,5

Elan Coil [88]

Yes, the rules of scientific notation are:

1. All non-zero digits are significant

2. Zeros in between non-zeros are significant.

3. Zeros to the left of the first non-zero number are NOT significant.

4. Zeros to the right of non-zero numbers are significant IF a decimal point is present.

P.S: if you need help with sig fig rounding, let me know.

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2 years ago

HELP I NEED HELP ASAP

ValentinkaMS [17]

Answer: B

Explanation:
We can substitute burgers for m and drinks for p, since all burgers are the same price and drinks are the same price, substitute the 3 burgers and 2 drinks into
3m+2p
The only right answer for this equation is $13.50, substitute the 5m+4p=$23.50 and your only right answer is B

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2 years ago

A recipe for spaghetti sauce requires 4 bottles of ketchup to make 2 gallons. How many bottles of ketchup are needed to make 10

frosja888 [35]

For 10 gallons of sauce, we need 5 times as required for 2 gallons, therefore we need 4 * 5 = 20 bottles of ketchup.

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2 years ago

The amount of time Ricardo spends brushing his teeth follows a Normal distribution with unknown mean and standard deviation. Ric

Papessa [141]

Let $X$ denote the number of minutes spent brushing his teeth, and let $\mu$ be the mean and $\sigma$ the standard deviation for this distribution.

$\mathbb P(X$

The z-score corresponding to this probability is approximately $z=-0.2533$ , which means

$\dfrac{1-\mu}\sigma=-0.2533\iff\mu-0.2533\sigma=1$

Next, (note the sign change)

$\mathbb P(X>2)=0.02\implies\mathbb P(X\le2)=\mathbb P\left(\dfrac{X-\mu}\sigma\le\dfrac{2-\mu}\sigma\right)=0.98$

The corresponding z-score is approximately $z=2.0538$ , so you have

$\dfrac{2-\mu}\sigma=2.0538\iff\mu+2.0538\sigma=2$

Solving the two equations for $\mu$ and $\sigma$ , you'll find that the mean is approximately $\mu=1.1098$ and the standard deviation is approximately $\sigma=0.4334$ .

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2 years ago