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marissa [1.9K]
1 year ago
12

Factor complete −2x2 + 10x.

Mathematics
1 answer:
mezya [45]1 year ago
6 0

The factors of the quadratic equation is (x + 1) and (x - 6)

Given,

The quadratic equation; -2x² + 10x + 12

We have to find the factors of this equation using quadratic formula;-

Quadratic formula;- \frac{-b(+-)\sqrt{b^{2} -4ac} }{2a}

Here,

a = -2, b = 10 and c = 12

Now,

\frac{-b(+-)\sqrt{b^{2} -4ac} }{2a} = \frac{-10(+-)\sqrt{10^{2} -4 . -2. 12} }{2.-2} = \frac{-10(+-)\sqrt{100 +96} }{-4} = (-10±14) ÷ -4

Solve for,

- 10 + 14 / -4 = -4/4 = -1

That is, (x + 1)

Solve for,

- 10 - 14 / -4 = -24/-4 = 6

That is,  (x - 6)

Therefore, the factors for the given quadratic equation is (x + 1) and (x - 6)

Learn more about quadratic formula here;

brainly.com/question/9300679

#SPJ1

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If f(x) = 5x, what is f–1(x)?
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We are given f(x) = 5x
and we are to find inverse of f(x).

Step 1:
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Step 3:
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f'(y) = y/5

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f'(x) = x/5

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Answer:

Step-by-step explanation:

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A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


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