Let the number of red, black, green and blue balls be R, B, G, U respectively.
B=R (There are as many black balls as red balls)
G+R=10 so G=10-R (Green balls and red balls should add up to 10)
R+10=U (There should be 10 more blue balls than red balls)
The minimal number of balls is 2, 304 so we have the following inequality:
R+B+G+U≥ 2,304
R+(R)+(10-R)+ (R+10)≥2,304
4R≥2,304
R≥2,304/4=576 so R=576
Answer: 576
Answer:
A = 5,752.60
Step-by-step explanation:
P = $3,500
r= 5%
t = 10
k = 4
A = P(1 + r/k)^kt
= 3,500(1 + 0.05/4)^4*10
= 3,500(1 + 0.0125)^40
= 3,500(1.0125)^40
= 3,500(1.6436)
= 5,752.6
A = 5,752.60
400(0.08)= T
T + 400= Commission or C
C • Weeks= X $750 • Weeks= X This is how to solve, I can help you further if you provide the options.
Answer:
2
Step-by-step explanation:
Estimate 1 2/11 to 1.
Estimate 2.97 to 3.
3 - 1 = 2
Answer:
-21
Step-by-step explanation: