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ValentinkaMS [17]
3 years ago
15

Which is the graph of f(x)=1/2x? Edg

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0

Answer:

There would be a line going directly through the x-asis

Step-by-step explanation:

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Which of the following number sentences is an example of the identity property of addition?
Paladinen [302]

Answer:

Option C is correct

8 + 0 = 8

Hope this helps!

:)

3 0
3 years ago
Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several
jonny [76]

A) A ratio system

B) The 4 lb peanuts and the 1 lb mixture because the 4lb added to the 1lb of mixture give the correct percentages.

4 0
3 years ago
Suppose that the weights of passengers on a flight to Greenland on Frigid Aire Lines are normal with mean 175 pounds and standar
Natali5045456 [20]

Answer:

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 175, \sigma = 22

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?

90th percentile

The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 175}{22}

X - 175 = 22*1.28

X = 203.16

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

6 0
3 years ago
Find the Least Common Multiple of these two monomials:
bonufazy [111]

LCM 14 & 24 = 168

then use the highest exponents for the variables

 answer = 168x^6y^6z^8

7 0
3 years ago
Solve |6k + 12| + 9 = 9 for k.
slavikrds [6]

Step-by-step explanation:

6k + 12 + 9=9

6k + 12 = 9 - 9

6k + 12 = 0

12 = -6k

12/-6 = -6k/-6

2/-1 = k

k = -2

6 0
3 years ago
Read 2 more answers
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