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Nataliya [291]
1 year ago
15

Use the vertex and a point on the parabola to write an equation in vertex form for the quadratic graph.

Mathematics
1 answer:
masya89 [10]1 year ago
4 0

By using the vertex and the given point of the parabola, we conclude that the equation is:

y = -1*(x - 2)^2 + 2

<h3>How to find the equation of the parabola?</h3>

For a parabola with a leading coefficient a and a vertex (h, k), the vertex form is:

y = a*(x - h)^2 + k

In this case, we can see that the vertex is (2, 2), replacing that we get:

y = a*(x - 2)^2 + 2

We also can see that the parabola passes through (0, -2) replacing that in the above equation we get:

-2 = a*(0 - 2)^2 + 2

-2 = a*4 + 2

-2 - 2= a*4

-4 = a*4

-4/4 = a

-1 = a

Then the equation for the parabola is:

y = -1*(x - 2)^2 + 2

Learn more about parabolas:

brainly.com/question/4061870

#SPJ1

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3 years ago
(HELP FOR 50 POINTS)
GrogVix [38]

y = 10x + 5 is the required equation.

Explanation:

A family of two to go to state fair is $25

A family of six to go to state fair is $65

So the 2 points are (2,25) and (6,65)

Rate of change = (y2-y1)/ (x2-x1)

 Plugin the values, we will get,

                          = (65 - 25)/ (6-2)= 40/4 = 10

Equation can be written as,

(y - y₁) / (y₂ - y₁) = (x-x₁)/(x₂-x₁)

(y-25)/(65-25) = (x-2)/(6-2)

(y-25)/ 40 = (x-2) / 4

4(y-25) = 40(x-2)

4y - 100 = 40x - 80

4y = 40x - 80 + 100

4y = 40x + 20

Dividing the equation by 4, we will get,

y = 10x + 5 is the equation required.

4 0
2 years ago
The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivati
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Ughhh...the limit formula...this should be thrown in the trash the minute you start doing derivatives :P

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(-8-9t-9d+8+9t)/d

-9d/d  (which is -9 for any value of d as well as when d approaches zero)

-9

So the instantaneous velocity is regardless of t or delta t


3 0
3 years ago
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7 0
2 years ago
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Answer: A  $3.00

i did the math to get $3.00 because you need to subtract

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