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Nataliya [291]
1 year ago
15

Use the vertex and a point on the parabola to write an equation in vertex form for the quadratic graph.

Mathematics
1 answer:
masya89 [10]1 year ago
4 0

By using the vertex and the given point of the parabola, we conclude that the equation is:

y = -1*(x - 2)^2 + 2

<h3>How to find the equation of the parabola?</h3>

For a parabola with a leading coefficient a and a vertex (h, k), the vertex form is:

y = a*(x - h)^2 + k

In this case, we can see that the vertex is (2, 2), replacing that we get:

y = a*(x - 2)^2 + 2

We also can see that the parabola passes through (0, -2) replacing that in the above equation we get:

-2 = a*(0 - 2)^2 + 2

-2 = a*4 + 2

-2 - 2= a*4

-4 = a*4

-4/4 = a

-1 = a

Then the equation for the parabola is:

y = -1*(x - 2)^2 + 2

Learn more about parabolas:

brainly.com/question/4061870

#SPJ1

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Step-by-step explanation:

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7 0
3 years ago
Identify the best big-O estimate for the number of comparisons used by the algorithm that determines the number of 1s in a bit s
Westkost [7]

Answer:

0(n)

Step-by-step explanation:

Result previous exercise:  

procedure count(a1a2...an : string with n > 1)

i:=0

for k:=1 to n

if ak =1 then i:=i + I

return i  

<em>Note</em><em>: If you use a different algorithm, then you could possible get different results.  </em>

<u>SOLUTION  </u>

There is only one part of the code that contains an operation (comparison), namely if a_k =1  

This comparison is executed in every iteration of the for-loop  

k can take on the values from 1 to n (for k:=I to n), thus k can take on n values.  

Thus in total there are then n comparisons, while n is 0(n).

5 0
3 years ago
You are assigned 32 math excercises for homework. You complete 87.5 of these before dinner. How many do you have left to do afte
Tcecarenko [31]
You would have 4 left:

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8 0
2 years ago
Read 2 more answers
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