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Gre4nikov [31]
3 years ago
14

2935.88 what is the value of digit 9

Mathematics
2 answers:
frez [133]3 years ago
6 0
900 is the correct answer
kondor19780726 [428]3 years ago
3 0
The value of  digit 9 is 900. It is in the hundreds place. Be sure not to confuse this with hundredths place because that is for the second decimal. (0.08) 
Hope this helps!
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BaLLatris [955]

Answer:

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax

​2

​​ +bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a

​2a

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​​

​​ )(x−

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​−b−√

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2 In this case, a=1a=1, b=-2b=−2 and c=-2c=−2.

(x-\frac{2+\sqrt{{(-2)}^{2}-4\times -2}}{2})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times -2}}{2})(x−

​2

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​2+√

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​​

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​​

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3 Simplify.

(x-\frac{2+2\sqrt{3}}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

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​2−2√

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4 Factor out the common term 22.

(x-\frac{2(1+\sqrt{3})}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

​2

​

​2(1+√

​3

​

​​ )

​​ )(x−

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​

​2−2√

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​​

​​ )

5 Cancel 22.

(x-(1+\sqrt{3}))(x-\frac{2-2\sqrt{3}}{2})(x−(1+√

​3

​

​​ ))(x−

​2

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​2−2√

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6 Simplify brackets.

(x-1-\sqrt{3})(x-\frac{2-2\sqrt{3}}{2})(x−1−√

​3

​

​​ )(x−

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7 Factor out the common term 22.

(x-1-\sqrt{3})(x-\frac{2(1-\sqrt{3})}{2})(x−1−√

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​​ )

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8 Cancel 22.

(x-1-\sqrt{3})(x-(1-\sqrt{3}))(x−1−√

​3

​

​​ )(x−(1−√

​3

​

​​ ))

9 Simplify brackets.

(x-1-\sqrt{3})(x-1+\sqrt{3})(x−1−√

​3

​

​​ )(x−1+√

​3

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