<u>Assuming that you want the product of the two factors given in each problem</u>:
⇒ we solve this problem by timing each unit of a factor to every unit
of the other factor
⇒then add each one of them who shares a common like-term
⇒to get the answer
<u>Let's solve:</u>
![(4m+n)(m-2n)=4m*m+(-2n)*4m+n*m+n(-2n)\\=4m^2-7nm-2n^2](https://tex.z-dn.net/?f=%284m%2Bn%29%28m-2n%29%3D4m%2Am%2B%28-2n%29%2A4m%2Bn%2Am%2Bn%28-2n%29%5C%5C%3D4m%5E2-7nm-2n%5E2)
![(2a-4b)(7a-2b)=2a*7a+(-2b)(2a)+(-4b)7a+(-4b)(-2b)\\=14a^2-4ab-28ab+8b^2\\=14a^2-32ab+8b^2](https://tex.z-dn.net/?f=%282a-4b%29%287a-2b%29%3D2a%2A7a%2B%28-2b%29%282a%29%2B%28-4b%297a%2B%28-4b%29%28-2b%29%5C%5C%3D14a%5E2-4ab-28ab%2B8b%5E2%5C%5C%3D14a%5E2-32ab%2B8b%5E2)
![(4m+1)^2=(4m+1)(4m+1)=4m*4m+4m*1+1*4m+1\\=16m^2+4m+4m+1\\=16m^2+8m+1](https://tex.z-dn.net/?f=%284m%2B1%29%5E2%3D%284m%2B1%29%284m%2B1%29%3D4m%2A4m%2B4m%2A1%2B1%2A4m%2B1%5C%5C%3D16m%5E2%2B4m%2B4m%2B1%5C%5C%3D16m%5E2%2B8m%2B1)
![(2w+1)(2w-1)=2w*2w+2w(-1)+1*(2w)+1(-1)\\=4w^2-1](https://tex.z-dn.net/?f=%282w%2B1%29%282w-1%29%3D2w%2A2w%2B2w%28-1%29%2B1%2A%282w%29%2B1%28-1%29%5C%5C%3D4w%5E2-1)
![(m+3)(m^2+4m+7)\\=m*m^2+m*4m+m*7+3m^2+3*4m+3*7\\=m^3+4m^2+7m+3m^2+12m+21\\=m^3+7m^2+19m+21](https://tex.z-dn.net/?f=%28m%2B3%29%28m%5E2%2B4m%2B7%29%5C%5C%3Dm%2Am%5E2%2Bm%2A4m%2Bm%2A7%2B3m%5E2%2B3%2A4m%2B3%2A7%5C%5C%3Dm%5E3%2B4m%5E2%2B7m%2B3m%5E2%2B12m%2B21%5C%5C%3Dm%5E3%2B7m%5E2%2B19m%2B21)
![(3x+2)(5x^2-12x-2)\\=3x*5x^2+3x(-12x)+3x(-2)+2(5x^2)+2(-12x)+2(-2)\\=15x^3-36x^2-6x+10x^2-24x-4\\=15x^3-26x^2-30x-4](https://tex.z-dn.net/?f=%283x%2B2%29%285x%5E2-12x-2%29%5C%5C%3D3x%2A5x%5E2%2B3x%28-12x%29%2B3x%28-2%29%2B2%285x%5E2%29%2B2%28-12x%29%2B2%28-2%29%5C%5C%3D15x%5E3-36x%5E2-6x%2B10x%5E2-24x-4%5C%5C%3D15x%5E3-26x%5E2-30x-4)
Hope that helps!
Answer:
3,400 J
Step-by-step explanation:
Got it off Kahn Academy, please just trust me on this.
Answer:
<h2>
<em><u>87</u></em></h2>
Step-by-step explanation:
<em>3×(5)^2 - 4×2 + 2×2×5</em>
<em>3×(5)^2 - 4×2 + 2×2×53×25 - 8 + 20</em>
<em>3×(5)^2 - 4×2 + 2×2×53×25 - 8 + 2075 + 20 - 8 </em>
<em>3×(5)^2 - 4×2 + 2×2×53×25 - 8 + 2075 + 20 - 8 95-8</em>
<em>3×(5)^2 - 4×2 + 2×2×53×25 - 8 + 2075 + 20 - 8 95-887</em>
A number with a zero in the ten's place needs to be at least a 3-digit number
So such a number can be 301, where 1 is at the unit's place, 0 is at the ten's place, and 3 is at the hundred's place
Please look at the image for reference.