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2 years ago

Help on my test very important

Mathematics

2 answers:

Rufina [12.5K]2 years ago

7 0

Hey buddy I am here to help!

The first one is false as the answer should be diameter = 9cm

The second one i dont know sry

Hope it helps!

vichka [17]2 years ago

5 0

1. False, the diameter has to be bigger than the radius.
2. True, tangent lines have to be perpendicular.

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WILL MARK BRAINLIEST A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is shown

Radda [10]

Answer:

a=567 km+900 km

a=1,467 km

b=567 km+169 km

b=736 km

x^2/a^2+y^2/b^2=1

x^2/(1,467)^2+y^2/(736)^2=1

Step-by-step explanation:

7 0

2 years ago

4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail

Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

$h^{-1}(x)=\sqrt{\frac{x+1}{3}}$ ⇒ answer D

Step-by-step explanation:

* Lets explain how to find the inverse of a function

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = $f^{-1}(x)$

* Lets use these steps to solve the problems

∵ $f(x)=\sqrt{x-3}$

∵ f(x) = y

∴ $y=\sqrt{x-3}$

- Exchange x and y

∴ $x=\sqrt{y-3}$

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by $f^{-1}(x)$

∴ $f^{-1}(x)=x^{2}+3$

∵ g(x) = x² + 3

∴ $f^{-1}(x)=g(x)$

∴ The functions are inverses to each other

* Now lets find f(g(x))

- To find f(g(x)) substitute x in f(x) by g(x)

∵ $f(x)=\sqrt{x-3}$

∵ g(x) = x² + 3

∴ $f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x$

∴ f(g(x)) = x

∴ The functions are inverses; f(g(x)) = x

* Lets find the inverse of h(x)

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ $\frac{x + 1}{3}=y^{2}$

- Take √ for both sides

∴ ± $\sqrt{\frac{x+1}{3}}=y$

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ $\sqrt{\frac{x+1}{3}}=y$

- replace y by $h^{-1}(x)$

∴ $h^{-1}(x)=\sqrt{\frac{x+1}{3}}$

4 0

2 years ago

You want to wrap a gift shaped like the regular triangular prism shown. How many square inches of wrapping paper do you need to

Tju [1.3M]

This would divide the x to 7 to get 86

8 0

1 year ago

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4). What is the y-coordinate of the midpoint of line segment YZ?

tatiyna

Given:

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).

To find:

The y-coordinate of the midpoint of line segment YZ.

Solution:

Midpoint formula:

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:

$Midpoint=\left(\dfrac{-3+7}{2},\dfrac{-6+4}{2}\right)$

$Midpoint=\left(\dfrac{4}{2},\dfrac{-2}{2}\right)$

$Midpoint=\left(2,-1\right)$

Therefore, the y-coordinate of the midpoint of line segment YZ is -1.

8 0

2 years ago

If f(x) = 4x – 20, what is f(4)? A. –12 B. –4 C. 16 D. 4

Lyrx [107]

It's B. You enter 4 instead of x on the right side and see what you get.

4 0

2 years ago

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