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1 year ago

14

From a standard deck of 52 playing cards what are the ODDS IN FAVOR of selecting an ace then a face card WITH REPLACEMENT.

1 answer:

Murljashka [212]1 year ago

7 0

The odds in favor of selecting an ace then a face card is 3/52.

<h3>What is the probability?</h3>

Probability is used to determine the odds in favor of an event happening. The odds in favor of an event happening lies between 0 and 1. The greater the odds in favor of the event happening, the closer to one, the probability value would be. In a deck of cards, there are 13 aces and there are 12 face cards

The odds in favor of selecting an ace then a face card = (number of ace cards / total number of cards) x (number of face cards / total number of cards)

(13 / 52) x (12 / 52)

1/4 x 3/13 = 3/52

To learn more about probability, please check: brainly.com/question/13234031

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at a parade, 1/4 of the participants have red hair, 1/6 of them have brown hair and the rest of them have black hair. which frac

netineya [11]

$\frac{1}{1}-\ all\ participants\\\\
\frac{1}{4}-\ participants\ with\ red\ hair\\\\ \frac{1}{6}-\ participants\ with\ brown\ hair\\\\
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6 0

3 years ago

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago

Jakebought a shirt for $12.50 and a pair of shoes for $49.99. Jakehad a coupon for 30% off the pair of shoes. Which expression c

Ymorist [56]

Answer:

u add the 50 and the 12.5 u get total of money then u put this total + 30÷100

7 0

2 years ago

1/2 + 2/9 + 27/53 as a fraction

nalin [4]

Answer:

1175/954 there your answer

5 0

2 years ago

X-5y=33<br> 5x-6y=70<br> solve the system by the addition method

BARSIC [14]

For this case we have the following system of equations:

$x-5y = 33\\5x-6y = 70$

We multiply the first equation by -5:

$-5x + 25y = -165$

Thus, we have the equivalent system:

$-5x + 25y = -165\\5x-6y = 70$

We add the equations:

$-5x + 5x + 25y-6y = -165 + 70\\19y = -95\\y = - \frac {95} {19}\\y = -5$

We find the value of the variable "x":

$x-5 (-5) = 33\\x + 25 = 33\\x = 33-25\\x = 8$

Thus, the solution of the system is:

$(x, y) :( 8, -5)$

Answer:

$(x, y) :( 8, -5)$

7 0

3 years ago