The line is called the directrix. Here we have a vertical directrix, so a parabola sideways from usual.
Geometry is best done with squared distances. The squared distance from an arbitrary point (x,y) to the vertical line x=2 is

We equate that to the squared distance of (x,y) to the focus (-2,0):


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We could call that done. A more standard form might be
Answer:
9.233 ft, 23.233 ft
Step-by-step explanation:
If the shorter leg is x, then the longer leg is x+14 and the Pythagorean theorem tells you ...
x^2 + (x +14)^2 = 25^2
2x^2 +28x +196 = 625
x^2 +14x = 214.5
x^2 +14x +49 = 263.5
(x +7)^2 = 263.5
x = -7 +√263.5 ≈ 9.23268
The two leg lengths are √263.5 ± 7 feet, {9.23 ft, 23.23 ft}.
Given: NQ = NT , QS Bisect NT(∴ NS=ST ) , TV Bisects QN (∴ NV=VQ )
To Prove: QS=TV
Proof: In ΔNQT
NQ=NT

∴ VQ=ST
In a isosceles triangle, If two sides are equal then their opposites angles are equal.
∴ ∠NQT=∠NTQ ( ∵ NQ=NT)
In ΔQST and TVQ
ST=VQ (sides of isosceles triangle)
∠NQT=∠NTQ (Prove above)
QT=TQ (Common)
So, ΔQST ≅ TVQ by SAS congruence property
∴ QS=TV (CPCT)
CPCT: Congruent part of congruence triangles.
Hence Proved
This would be a scalene triangle, because all of the sides are different lengths.
The correct answer is C.
Step-by-step explanation:
Given f(x) = 5x - 7 and g(x) = x² - 3, find f(f(2))