the perimeter of football field in a rectangular form of a certain school is 296cm if the breath is2/3 of the length find the le
ngth field
2 answers:
Answer:
L = 29.6 cm
Step-by-step explanation:
Let Length be L and Breadth be B
<u><em>Condition 1:</em></u>
![2(Length)+2(Breadth) = Perimeter](https://tex.z-dn.net/?f=2%28Length%29%2B2%28Breadth%29%20%3D%20Perimeter)
Where Perimeter = 296 cm
=> 2L + 2B = 296
=> 2(L+B) = 296
<em>Dividing both sides by 2</em>
=> L + B = 148 ------------------(1)
<u><em>Condition 2:</em></u>
=> B =
-------------------------(2)
Putting Equation 2 in 1
=> L +
= 148
Multiplying both sides by 3
=> 3L + 2L = 148
=> 5L = 148
=> L = 148/5
=> L = 29.6 cm
Turn the words into math symbols. This is an exercise in abstract substitution.
P = perimeter
Breath = Width
Perimeter = L+L+W+W
So…
P = 296
296 = L+L+W+ W
W=2/3* L
296 = L+L+2/3L+2/3L
296 = 2L+ 4/3 L
296 = 10/3 L
Multiply both sides by three…
888 = 10L
88.8 = L
Calculate in reverse to double check…
88.8+88.8+59.2+59.2 = 296
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