Answer is 526 because you need to find Area of the Front face multiplied by two area of the side face multiply that by two and then area of the top face and multiply that by two and then add them togetherDid you get an answer of 526. Hope it helps
Answer:
All the properties of a rhombus apply (the ones that matter here are parallel sides, diagonals are perpendicular bisectors of each other, and diagonals bisect the angles). All the properties of a rectangle apply (the only one that matters here is diagonals are congruent). All sides are congruent by definition.
<em>Angle </em><em>ADG,</em><em> </em><em>angle</em><em> </em><em>BEH </em><em>and </em><em>angle</em><em> </em><em>CFI,</em><em> </em><em>all </em><em>have </em><em>two </em><em>curves</em><em> </em><em>in </em><em>their</em><em> </em><em>angles</em><em>.</em><em> </em><em>Same </em><em>number</em><em> of</em><em> </em><em>curves</em><em> </em><em>are </em><em>used</em><em> </em><em>to </em><em>represent</em><em> </em><em>that </em><em>their</em><em> </em><em>measure</em><em> </em><em>are </em><em>equal</em><em>.</em><em> </em>
So, m angle CFI = m angle ADG
So, m angle CFI = m angle ADG=> m angle CFI = 92°
Any time you are rounding anything below 4 becomes a zero anything above a 5 is like a ten
ex.
Q. round to the nearest hundredth 3.24
A. 3.20
Q. round to the nearest hundrerg4 3.25
3.30
which means your answer is
4.40
Answer:
13
Step-by-step explanation:
Its calculate the common difference first.
(95-11)/(n-1).
We also have the sum of these n terms is 689.
So we have the following:
11
+(11+(95-11)/(n-1))
+(11+2(95-11)/(n-1))
+...
+(11+(n-1)(95-11)/(n-1))
This can be re-expressed alittle:
There are (n) amount of 11's in the addition... also 1+2+3+...+(n-1)=(n-1)(n)/2.
So we have the sum is
11(n)+n(n-1)/2×(95-11)/(n-1)
But this equal to 689.
We need to solve the following equation:
11(n)+n(n-1)/2×(95-11)/(n-1)=689
The (n-1)'s in second term can cancel.
11(n)+n/2×84=689
11n+42n=689
53n=689
53n=689
n=689/53
n=13
