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3 years ago

HELLLLLLPPPP PLEASEEEEEEEEEEE

Mathematics

1 answer:

dalvyx [7]3 years ago

8 0

What I’m I supposed to be looking for??

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Please help marking brainliest if correct!!

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

2x=5x+60.

0=3x+60 ( subtract 2x from both sides)

-60=3x(subtract 60 on both sides)

x=-20

Hope this helps plz mark brainliest if correct :D

6 0

2 years ago

Read 2 more answers

Help anyone can help me do the question 4,I will mark brainlest.

nasty-shy [4]

Answer:

Hello,

Step-by-step explanation:

$A=(1,2)\\B=(0,-1)\\\overrightarrow{AB}=((0,-1)-(1,2)=(-1,-3)\ ||\overrightarrow{AB}||^2=1+9=10\\\overrightarrow{BC}=((3,-2)-(0,-1)=(3,-1)\ ||\overrightarrow{BC}||^2=9+1=10\\\\Triangle\ is\ isosceles.\\\\\overrightarrow{AB}.\overrightarrow{BC}=(-1,-3)*\left[\begin{array}{c}3\\-1\end{array}\right] =-3+3=0\\\\Triangle \ is\ right.\\\\$

8 0

2 years ago

Read 2 more answers

Find the volume. SHOW WORK

Anettt [7]

Answer:

827.39

Step-by-step explanation:

Volume = L X W X H

So 6.2 X 8.5 X 15.7

6.2 X 8.5 = 52.7

52.7 X 15.7 = 827.39

So the volume is <u>827.39</u>

3 0

2 years ago

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Solve the equation -31=-6z-4z

jok3333 [9.3K]

<span>-31=-6z-4z
Subtract 4z from -6z
-31=-10z
Divide both sides by -10
Final Answer: 3.1 or 3 1/10</span>

8 0

2 years ago

Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$

Viktor [21]

When $n=0$ , we have

$5^{3^0} + 1 = 5^1 + 1 = 6$

$3^{0 + 1} = 3^1 = 3$

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for $n=k$ , that

$3^{k + 1} \mid 5^{3^k} + 1$

Now for $n=k+1$ , we have

$5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)$