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Paul [167]
1 year ago
12

The table shows the relationship between a hedgehog's

Mathematics
1 answer:
Tpy6a [65]1 year ago
6 0

The weight would the hedgehog lose during 115 day in hibernation is 3.45 ounces.

<h3>How much weight would the hedgehog lose during 115 day in hibernation?</h3>

Using proportions, it exits found that the hedgehog loses 3.45 ounces after 115 days of hibernation.

A proportional relationship exists modeled by: y = kx

In which k exists the constant of proportionality.

In this problem, the ratio between the weight loss after x days in hibernation is given by:

k = 0.24/8 = 0.84/24 = 2.25/75 = 2.79/93 = 0.03

Since this ratio exists constant, the relationship is proportional, modeled by:

y = 0.03 x

The weight lost after 115 days of hibernation is y(115), hence:

y = 0.03(115) = 3.45

The hedgehog loses 3.45 ounces after 115 days of hibernation.

To learn more about hedgehog weight loss refer to:

brainly.com/question/24372153

#SPJ9

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x - y = 35
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Jenni has a box of chocolates. There are 15 pieces of dark chocolate and 25 pieces of milk chocolate in the box. What is the rat
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What is 10 squared plus b squared equals 22 squared
klio [65]
I'm pretty sure you are asking for the value of b. Let's actually write it and then solve it:
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So, b = 19.59. If you want the answer in simplified radical form, we can also do that:
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13 POINTS- please help me
allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17

Then

(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}

19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}

Check:

34^{\circ}+56^{\circ}=90^{\circ}

20. Angles \angle 1 and \angle 2 are vertical angles. By vertical angles theorem, vertical angles are congruent, so

m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4

Hence,

m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

21. \angle 5 and \angle 8 are supplementary. The measures of supplementary angles add up to 180^{\circ}, so

m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34

Therefore,

m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}

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