Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
Answer:
The original regular price for the coat is $90
Step-by-step explanation:
The given information in the question are;
The percentage that was off (removed) from the sale price = 30%
The sale price at which Jerry bought the coat = $63
Whereby the regular price = P, we have;
P - 30% of P = $63
P - 0.3×P = $63
P×(1 - 0.3) = $63
0.7·P = $63
P = $63/0.7 = $90
Therefore, the regular (original) price for the coat = $90
The coat regular price at which the coat is displayed is at $90.
