F = kq2 / r2
q = ne
F = k(ne)2 / r2
n = âš(r2F / ke2) = (r/e) âš(F/k)
k = 9 x 109 Nm2/C2
e = 1.6 x 10-19 C
n = [(4.2 x 10-10) / (1.6 x 10-19)] âš[(5.2 x 10-9) / (9 x 109)] ≅ 1.995 ≅ 2
7 hours is 28 quarter hours. 50 is closer to 45 than 00 so it is. 75 hours. total is 28.75
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Let the number = x.
So 2 times x subtracted from 11 is written as 11-2x
The result is 4 more than the number is written as 4 +x
Now you have 11-2x = 4 + x
We can now solve for x.
Add 2x to each side:
11 = 4 + 3x
Subtract 4 from each side:
7 = 3x
Divide both sides by 3:
x = 7/3