Answer:
3p² + 32p + 13
Step-by-step explanation:
Okay, so lets first solve for 2b. 2b = 2(p + 5), which is equal to 2p + 10. Now, let's solve for 3a. 3a = 3(p² + 10p +1), simplifying to 3p² + 30p +3. After adding 2b and 3a, we are able to get 2p + 10 + 3p² + 30p + 3 = 3p² + 32p + 13
Answer:
Angle N should be 64
Step-by-step explanation:
A triangle adds up to 180. So triangle JKL already has 60 towards 180. Triangle ONM already has 56 towards 180. So you have to find the other value needed in order to make 180. 56+60= 116 so we need to find the other angle to make 180. To do so just subtract 180-116 and that gives tou the answer 64 so that would be Angle N
Answer:
-2.4-(-7) has the same result as -2+7 because the negative sign and the minus sign cancel each other out. Think of it like this. If you cross the negative sign and the minus sign together, then it makes a plus sign.
Step-by-step explanation:
I gave a basic answer. You might have to elaborate more on this.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
I'm doing 3
For 3, using a table is very similar to a double number because the numbers are matching up in both ways.
On the bottom of a double number line we have like, for example,-- the bottom of the double number line would have batches. And its 1, 2, 3 ,4 , etc.
And on a table, it would be the same, the numbers on both diagrams have the same methods, have same way of lining things up but they're just drawn differently.
Hope this helped!
